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JEE Main Mathematics · Class 11

Composition of functions — NEET & JEE Questions

Composition of functions is a topic in Sets, Relations and Functions, a Class 11 Mathematics chapter of the JEE Main syllabus. TestBudy holds 27 published JEE Main questions on Composition of functions, each with the marking scheme of the real paper.

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Composition of functions MCQs with solutions

10 of the 27 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L3 · understanding

    For some a, b, c ∈N\in\mathbb{N}, let f(x)=ax−3f(x) = ax - 3 and g(x)=xb+c,x∈R\mathrm{g(x)=x^b+c,x\in\mathbb{R}}. If (fog)−1(x)=(x−72)1/3{(fog)^{ - 1}}(x) = {\left( {{{x - 7} \over 2}} \right)^{1/3}}, then (fog)(ac)+(gof)(b)(fog)(ac) + (gof)(b) is equal to ____________.

  2. Question 2 · difficulty L3 · understanding

    Let f(x) and g(x) be two real polynomials of degree 2 and 1 respectively. If f(g(x))=8x2−2xf(g(x)) = 8{x^2} - 2x and g(f(x))=4x2+6x+1g(f(x)) = 4{x^2} + 6x + 1, then the value of f(2)+g(2)f(2) + g(2) is _________.

  3. Question 3 · difficulty L3 · understanding

    Let S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Define f : S →\to S as \begin{aligned}f(n) = \left\{ {\matrix{ {2n} & , & {if\,n = 1,2,3,4,5} \cr {2n - 11} & , & {if\,n = 6,7,8,9,10} \cr } } \right.\end{aligned}. Let g : S →\to S be a function such that \begin{aligned}fog(n) = \left\{ {\matrix{ {n + 1} & , & {if\,n\,\,is\,odd} \cr {n - 1} & , & {if\,n\,\,is\,even} \cr } } \right.\end{aligned}. Then g(10)g(1)+g(2)+g(3)+g(4)+g(5))g(10)g(1) + g(2) + g(3) + g(4) + g(5)) is equal to _____________.

  4. Question 4 · difficulty L3 · understanding

    Let f:R→Rf:R \to R be a function defined by f(x)=(2(1−x252)(2+x25))150f(x) = {\left( {2\left( {1 - {{{x^{25}}} \over 2}} \right)(2 + {x^{25}})} \right)^{{1 \over {50}}}}. If the function g(x)=f(f(f(x)))+f(f(x))g(x) = f(f(f(x))) + f(f(x)), then the greatest integer less than or equal to g(1) is ____________.

  5. Question 5 · difficulty L3 · understanding

    If g(x)=3x2+2x−3,f(0)=−3g(x)=3 x^2+2 x-3, f(0)=-3 and 4g(f(x))=3x2−32x+724 g(f(x))=3 x^2-32 x+72, then f(g(2))f(g(2)) is equal to:

    • A. 72\frac{7}{2}
    • B. −256-\frac{25}{6}
    • C. 256\frac{25}{6}
    • D. −72-\frac{7}{2}
  6. Question 6 · difficulty L3 · understanding

    Let f(x)=log⁡exf(x)=\log _{\mathrm{e}} x and g(x)=x4−2x3+3x2−2x+22x2−2x+1g(x)=\frac{x^4-2 x^3+3 x^2-2 x+2}{2 x^2-2 x+1}. Then the domain of f∘gf \circ g is

    • A. (0,∞)(0, \infty)
    • B. [1,∞)[1, \infty)
    • C. R\mathbb{R}
    • D. [0,∞)[0, \infty)
  7. Question 7 · difficulty L3 · understanding

    Let f,g:R→Rf, g: \mathbf{R} \rightarrow \mathbf{R} be defined as : f(x)=∣x−1∣ and g(x)={ex,x≥0x+1,x≤0.f(x)=|x-1| \text { and } g(x)= \begin{cases}\mathrm{e}^x, & x \geq 0 \\ x+1, & x \leq 0 .\end{cases} Then the function f(g(x))f(g(x)) is

    • A. neither one-one nor onto.
    • B. one-one but not onto.
    • C. both one-one and onto.
    • D. onto but not one-one.
  8. Question 8 · difficulty L3 · understanding

    Let f:R→Rf: \mathbf{R} \rightarrow \mathbf{R} and g:R→Rg: \mathbf{R} \rightarrow \mathbf{R} be defined as $f(x)=\left\{log⁡ex,x>0e−x,x≤0\begin{array}{ll}\log _{\mathrm{e}} x, & x>0 \\ \mathrm{e}^{-x}, & x \leq 0\end{array}\right.and and g(x)=\left\{x,x⩾0ex,x<0\begin{array}{ll}x, & x \geqslant 0 \\ \mathrm{e}^x, & x<0\end{array}\right..Then,gof:. Then, gof : \mathbf{R} \rightarrow \mathbf{R}$ is :

    • A. one-one but not onto
    • B. neither one-one nor onto
    • C. onto but not one-one
    • D. both one-one and onto
  9. Question 9 · difficulty L3 · understanding

    If f(x)=4x+36x−4,x≠23f(x)=\frac{4 x+3}{6 x-4}, x \neq \frac{2}{3} and (f∘f)(x)=g(x)(f \circ f)(x)=g(x), where g:R−{23}→R−{23}g: \mathbb{R}-\left\{\frac{2}{3}\right\} \rightarrow \mathbb{R}-\left\{\frac{2}{3}\right\}, then (gogog)(4)(g ogog)(4) is equal to

    • A. −4-4
    • B. 1920\frac{19}{20}
    • C. −1920-\frac{19}{20}
    • D. 4
  10. Question 10 · difficulty L3 · understanding

    If f(x)={2+2x,−1≤x<01−x3,0≤x≤3;g(x)={−x,−3≤x≤0x,0<x≤1f(x)=\left\{\begin{array}{cc}2+2 x, & -1 \leq x < 0 \\ 1-\frac{x}{3}, & 0 \leq x \leq 3\end{array} ; g(x)=\left\{\begin{array}{cc}-x, & -3 \leq x \leq 0 \\ x, & 0 < x \leq 1\end{array}\right.\right., then range of (fog)(x)(f o g)(x) is

    • A. [0,1)[0,1)
    • B. [0,3)[0,3)
    • C. (0,1](0,1]
    • D. [0,1][0,1]

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