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JEE Main Mathematics · Class 12

Adjoint and inverse of a square matrix — NEET & JEE Questions

Adjoint and inverse of a square matrix is a topic in Matrices and Determinants, a Class 12 Mathematics chapter of the JEE Main syllabus. TestBudy holds 48 published JEE Main questions on Adjoint and inverse of a square matrix, each with the marking scheme of the real paper.

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Adjoint and inverse of a square matrix MCQs with solutions

10 of the 48 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L2 · understanding

    If the ad joint of a 3 ×\times 3 matrix P is \begin{aligned}\left[ {\matrix{ 1 & 4 & 4 \cr 2 & 1 & 7 \cr 1 & 1 & 3 \cr } } \right]\end{aligned}, then the possible value(s) of the determinant of P is(are)

    • A. −-2
    • B. −-1
    • C. 1
    • D. 2
  2. Question 2 · difficulty L3 · understanding

    Let $A=\left[−11−1101001\begin{array}{ccc}-1 & 1 & -1 \\ 1 & 0 & 1 \\ 0 & 0 & 1\end{array}\right]satisfy satisfy \mathrm{A}^2+\alpha(\operatorname{adj}(\operatorname{adj}(\mathrm{A})))+\beta(\operatorname{adj}(\mathrm{A})(\operatorname{adj}(\operatorname{adj}(\mathrm{A}))))=\left[2−22−20−100−1\begin{array}{ccc}2 & -2 & 2 \\ -2 & 0 & -1 \\ 0 & 0 & -1\end{array}\right]forsome for some \alpha, \beta \in \mathbb{R}.Then. Then (\alpha-\beta)^2isequalto is equal to \_\_\_\_$

  3. Question 3 · difficulty L3 · understanding

    Consider the matrices $A = [2−24−2]\begin{bmatrix} 2 & -2 \\ 4 & -2 \end{bmatrix}and and B = [3913]\begin{bmatrix} 3 & 9 \\ 1 & 3 \end{bmatrix}.Ifmatrices. If matrices Pand and Qaresuchthat are such that PA = Band and AQ = B,thentheabsolutevalueofthesumofthediagonalelementsof, then the absolute value of the sum of the diagonal elements of 2(P + Q)$ is ________.

  4. Question 4 · difficulty L3 · understanding

    Let $A=\left[02−3−2013−10\begin{array}{ccc}0 & 2 & -3 \\ -2 & 0 & 1 \\ 3 & -1 & 0\end{array}\right]and and Bbeamatrixsuchthat be a matrix such that B(I-A)=I+A.Thenthesumofthediagonalelementsof. Then the sum of the diagonal elements of \mathrm{B}^{\mathrm{T}} \mathrm{B}isequalto is equal to \_\_\_\_$

  5. Question 5 · difficulty L3 · understanding

    For some α,β∈R\alpha, \beta \in \mathbf{R}, let $A=\left[α212\begin{array}{ll}\alpha & 2 \\ 1 & 2\end{array}\right]and and B=\left[111β\begin{array}{ll}1 & 1 \\ 1 & \beta\end{array}\right]besuchthat be such that A^2-4 A+2 I=B^2-3 B+I=O.Then. Then \left(\operatorname{det}\left(\operatorname{adj}\left(A^3-B^3\right)\right)\right)^2isequalto is equal to \_\_\_\_$ .

  6. Question 6 · difficulty L3 · understanding

    Let S={m∈Z:Am2+Am=3I−A−6}S=\left\{m \in \mathbf{Z}: A^{m^2}+A^m=3 I-A^{-6}\right\}, where $A=\left[2−110\begin{array}{cc}2 & -1 \\ 1 & 0\end{array}\right].Then. Then n(S)$ is equal to __________.

  7. Question 7 · difficulty L3 · understanding

    Let AA be a square matrix of order 3 such that det⁡(A)=−2\operatorname{det}(A)=-2 and det⁡(3adj⁡(−6adj⁡(3A)))=2m+n⋅3mn,m>n\operatorname{det}(3 \operatorname{adj}(-6 \operatorname{adj}(3 A)))=2^{m+n} \cdot 3^{m n}, m>n. Then 4m+2n4 m+2 n is equal to __________.

  8. Question 8 · difficulty L3 · understanding

    Let AA be a 2×22 \times 2 symmetric matrix such that A[11]=[37]A\left[\begin{array}{l}1 \\ 1\end{array}\right]=\left[\begin{array}{l}3 \\ 7\end{array}\right] and the determinant of AA be 1 . If A−1=αA+βIA^{-1}=\alpha A+\beta I, where II is an identity matrix of order 2×22 \times 2, then α+β\alpha+\beta equals _________.

  9. Question 9 · difficulty L3 · understanding

    The number of matrices A=(abcd)A=\left(\begin{array}{ll}a & b \\ c & d\end{array}\right), where a,b,c,d∈{−1,0,1,2,3,……,10}a, b, c, d \in\{-1,0,1,2,3, \ldots \ldots, 10\}, such that A=A−1A=A^{-1}, is ___________.

  10. Question 10 · difficulty L3 · understanding

    Let \begin{aligned}X = \left[ {\matrix{ 0 & 1 & 0 \cr 0 & 0 & 1 \cr 0 & 0 & 0 \cr } } \right],\,Y = \alpha I + \beta X + \gamma {X^2}\end{aligned} and Z=α2I−αβX+(β2−αγ)X2Z = {\alpha ^2}I - \alpha \beta X + ({\beta ^2} - \alpha \gamma ){X^2}, α\alpha, β\beta, γ\gamma ∈\in R. If \begin{aligned}{Y^{ - 1}} = \left[ {\matrix{ {{1 \over 5}} & {{{ - 2} \over 5}} & {{1 \over 5}} \cr 0 & {{1 \over 5}} & {{{ - 2} \over 5}} \cr 0 & 0 & {{1 \over 5}} \cr } } \right]\end{aligned}, then (α\alpha −- β\beta + γ\gamma) 2 is equal to ____________.

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