Skip to content

JEE Main Mathematics · Class 11

Properties of binomial coefficients — NEET & JEE Questions

Properties of binomial coefficients is a topic in Binomial Theorem and Its Simple Applications, a Class 11 Mathematics chapter of the JEE Main syllabus. TestBudy holds 75 published JEE Main questions on Properties of binomial coefficients, each with the marking scheme of the real paper.

questions
75
shown here
10
Test me on this topic

Five free tests with an account. Your score comes with the result; where you stand is Pro.

Properties of binomial coefficients MCQs with solutions

10 of the 75 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L2 · understanding

    If A denotes the sum of all the coefficients in the expansion of (1−3x+10x2)n\left(1-3 x+10 x^2\right)^{\mathrm{n}} and B denotes the sum of all the coefficients in the expansion of (1+x2)n\left(1+x^2\right)^n, then :

    • A. B=A3\mathrm{B}=\mathrm{A}^3
    • B. 3A=B3 \mathrm{A}=\mathrm{B}
    • C. A=3BA=3 B
    • D. A=B3\mathrm{A}=\mathrm{B}^3
  2. Question 2 · difficulty L2 · understanding

    Let [ x ] denote greatest integer less than or equal to x. If for n∈\inN, (1−x+x3)n=∑j=03najxj{(1 - x + {x^3})^n} = \sum\limits_{j = 0}^{3n} {{a_j}{x^j}} , then ∑j=0[3n2]a2j+4∑j=0[3n−12]a2j+1\sum\limits_{j = 0}^{\left[ {{{3n} \over 2}} \right]} {{a_{2j}} + 4} \sum\limits_{j = 0}^{\left[ {{{3n - 1} \over 2}} \right]} {{a_{2j}} + 1} is equal to :

    • A. 2 n −- 1
    • B. n
    • C. 2
    • D. 1
  3. Question 3 · difficulty L2 · understanding

    The coefficient of x18x^{18} in the expansion of (x4−1x3)15\left(x^{4}-\frac{1}{x^{3}}\right)^{15} is __________.

  4. Question 4 · difficulty L2 · understanding

    If the sum of the coefficients in the expansion of (x + y) n is 4096, then the greatest coefficient in the expansion is _____________.

  5. Question 5 · difficulty L3 · understanding

    If for 3≤r≤303 \leq r \leq 30, (30C30−r)+3(30C31−r)+3(30C32−r)+(30C33−r)=mCr\left({^{30}C_{30-r}}\right) + 3\left({^{30}C_{31-r}}\right) + 3\left({^{30}C_{32-r}}\right) + \left({^{30}C_{33-r}}\right) = {^mC_r}, then m equals :

    • A. 31
    • B. 32
    • C. 33
    • D. 34
  6. Question 6 · difficulty L3 · understanding

    The sum of the coefficients of x499x^{499} and x500x^{500} in (1+x)1000+x(1+x)999+x2(1+x)998+…+x1000(1 + x)^{1000} + x(1 + x)^{999} + x^2(1 + x)^{998} + \ldots + x^{1000} is :

    • A. 1002C501{ }^{1002} C_{501}
    • B. 1001C501{ }^{1001} C_{501}
    • C. 1000C501{ }^{1000} C_{501}
    • D. 1002C500{ }^{1002} C_{500}
  7. Question 7 · difficulty L3 · understanding

    Let S=125!+13!23!+15!21!+…\mathrm{S}=\frac{1}{25!}+\frac{1}{3!23!}+\frac{1}{5!21!}+\ldots up to 13 terms. If 13 S=2kn!,k∈ N13 \mathrm{~S}=\frac{2^k}{n!}, k \in \mathrm{~N}, then n+kn+k is equal to

    • A. 50
    • B. 52
    • C. 49
    • D. 51
  8. Question 8 · difficulty L3 · understanding

    The sum of all possible values of n∈N\mathbf{n} \in \mathbf{N}, so that the coefficients of x,x2x, x^2 and x3x^3 in the expansion of (1+x2)2(1+x)n\left(1+x^2\right)^2(1+x)^{\mathrm{n}}, are in arithmetic progression is :

    • A. 12
    • B. 9
    • C. 3
    • D. 7
  9. Question 9 · difficulty L3 · understanding

    The value of 100C5051+100C5152+….+100C100101\frac{{ }^{100} \mathrm{C}_{50}}{51}+\frac{{ }^{100} \mathrm{C}_{51}}{52}+\ldots .+\frac{{ }^{100} \mathrm{C}_{100}}{101} is:

    • A. 2101101\frac{2^{101}}{101}
    • B. 2100101\frac{2^{100}}{101}
    • C. 2100100\frac{2^{100}}{100}
    • D. 2101100\frac{2^{101}}{100}
  10. Question 10 · difficulty L3 · understanding

    The coefficient of x48x^{48} in (1+x)+2(1+x)2+3(1+x)3+…+100(1+x)100(1+x)+2(1+x)^2+3(1+x)^3+\ldots+100(1+x)^{100} is equal to

    • A. 100⋅100C49−100C48100 \cdot{ }^{100} \mathrm{C}_{49}-{ }^{100} \mathrm{C}_{48}
    • B. 100⋅101C49−101C50100 \cdot{ }^{101} \mathrm{C}_{49}-{ }^{101} \mathrm{C}_{50}
    • C. 100C50+101C49{ }^{100} \mathrm{C}_{50}+{ }^{101} \mathrm{C}_{49}
    • D. 100⋅100C49−100C50100 \cdot{ }^{100} \mathrm{C}_{49}-{ }^{100} \mathrm{C}_{50}

Practise this chapter

Reading a question and answering it under a clock are different things. A chapter-length test measures whether the topic went in.