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JEE Main Mathematics · Class 12

Differentiation of trigonometric, logarithmic, exponential, composite and implicit functions — NEET & JEE Questions

Differentiation of trigonometric, logarithmic, exponential, composite and implicit functions is a topic in Limit, Continuity and Differentiability, a Class 12 Mathematics chapter of the JEE Main syllabus. TestBudy holds 31 published JEE Main questions on Differentiation of trigonometric, logarithmic, exponential, composite and implicit functions, each with the marking scheme of the real paper.

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Differentiation of trigonometric, logarithmic, exponential, composite and implicit functions MCQs with solutions

10 of the 31 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L2 · understanding

    Let f:R−{0}→Rf: \mathbb{R}-\{0\} \rightarrow \mathbb{R} be a function satisfying f(xy)=f(x)f(y)f\left(\frac{x}{y}\right)=\frac{f(x)}{f(y)} for all x,y,f(y)≠0x, y, f(y) \neq 0. If f′(1)=2024f^{\prime}(1)=2024, then

    • A. xf′(x)+2024f(x)=0x f^{\prime}(x)+2024 f(x)=0
    • B. xf′(x)−2023f(x)=0x f^{\prime}(x)-2023 f(x)=0
    • C. xf′(x)−2024f(x)=0x f^{\prime}(x)-2024 f(x)=0
    • D. xf′(x)+f(x)=2024x f^{\prime}(x)+f(x)=2024
  2. Question 2 · difficulty L3 · understanding

    Let f(x)=\sum_\limits{k=1}^{10} k x^{k}, x \in \mathbb{R}. If 2f(2)+f′(2)=119(2)n+12 f(2)+f^{\prime}(2)=119(2)^{\mathrm{n}}+1 then n\mathrm{n} is equal to ___________

  3. Question 3 · difficulty L3 · understanding

    Let f1(x)=3x+22x+3,x∈R−{−32}f^{1}(x)=\frac{3 x+2}{2 x+3}, x \in \mathbf{R}-\left\{\frac{-3}{2}\right\} For n≥2\mathrm{n} \geq 2, define fn(x)=f1ofn−1(x)f^{\mathrm{n}}(x)=f^{1} \mathrm{o} f^{\mathrm{n}-1}(x). If f5(x)=ax+bbx+a,gcd⁡(a,b)=1f^{5}(x)=\frac{\mathrm{a} x+\mathrm{b}}{\mathrm{b} x+\mathrm{a}}, \operatorname{gcd}(\mathrm{a}, \mathrm{b})=1, then a+b\mathrm{a}+\mathrm{b} is equal to ____________.

  4. Question 4 · difficulty L3 · understanding

    Let f : R →\to R satisfy f(x+y)=2xf(y)+4yf(x)f(x + y) = {2^x}f(y) + {4^y}f(x), ∀\forallx, y ∈\in R. If f(2) = 3, then 14. f′(4)f′(2)14.\,{{f'(4)} \over {f'(2)}} is equal to ____________.

  5. Question 5 · difficulty L3 · understanding

    Suppose for a differentiable function h,h(0)=0,h(1)=1h, h(0)=0, h(1)=1 and h′(0)=h′(1)=2h^{\prime}(0)=h^{\prime}(1)=2. If g(x)=h(ex)eh(x)g(x)=h\left(\mathrm{e}^x\right) \mathrm{e}^{h(x)}, then g′(0)g^{\prime}(0) is equal to:

    • A. 4
    • B. 5
    • C. 3
    • D. 8
  6. Question 6 · difficulty L3 · understanding

    Let f(x)=x5+2ex/4f(x)=x^5+2 \mathrm{e}^{x / 4} for all x∈Rx \in \mathbf{R}. Consider a function g(x)g(x) such that (g∘f)(x)=x(g \circ f)(x)=x for all x∈Rx \in \mathbf{R}. Then the value of 8g′(2)8 g^{\prime}(2) is :

    • A. 4
    • B. 2
    • C. 16
    • D. 8
  7. Question 7 · difficulty L3 · understanding

     Let y=log⁡e(1−x21+x2),−1<x<1. Then at x=12, the value of 225(y′−y′′) is equal to \text { Let } y=\log _e\left(\frac{1-x^2}{1+x^2}\right),-1 < x<1 \text {. Then at } x=\frac{1}{2} \text {, the value of } 225\left(y^{\prime}-y^{\prime \prime}\right) \text { is equal to }

    • A. 732
    • B. 736
    • C. 742
    • D. 746
  8. Question 8 · difficulty L3 · understanding

    Let f(x)=sin⁡x+cos⁡x−2sin⁡x−cos⁡x,x∈[0,π]−{π4}f(x)=\frac{\sin x+\cos x-\sqrt{2}}{\sin x-\cos x}, x \in[0, \pi]-\left\{\frac{\pi}{4}\right\}. Then f(7π12)f′′(7π12)f\left(\frac{7 \pi}{12}\right) f^{\prime \prime}\left(\frac{7 \pi}{12}\right) is equal to

    • A. 233\frac{2}{3 \sqrt{3}}
    • B. 29\frac{2}{9}
    • C. −133\frac{-1}{3 \sqrt{3}}
    • D. −23\frac{-2}{3}
  9. Question 9 · difficulty L3 · understanding

    If 2xy+3yx=202 x^{y}+3 y^{x}=20, then dydx\frac{d y}{d x} at (2,2)(2,2) is equal to :

    • A. −(3+log⁡e164+log⁡e8)-\left(\frac{3+\log _{e} 16}{4+\log _{e} 8}\right)
    • B. −(2+log⁡e83+log⁡e4)-\left(\frac{2+\log _{e} 8}{3+\log _{e} 4}\right)
    • C. −(3+log⁡e82+log⁡e4)-\left(\frac{3+\log _{e} 8}{2+\log _{e} 4}\right)
    • D. −(3+log⁡e42+log⁡e8)-\left(\frac{3+\log _{e} 4}{2+\log _{e} 8}\right)
  10. Question 10 · difficulty L3 · understanding

    If y(x)=xx,x>0y(x)=x^{x},x > 0, then y′′(2)−2y′(2)y''(2)-2y'(2) is equal to

    • A. 4(log⁡e2)2+24(\log_{e}2)^{2}+2
    • B. 8log⁡e2−28\log_{e}2-2
    • C. 4log⁡e2+24\log_{e}2+2
    • D. 4(log⁡e2)2−24(\log_{e}2)^{2}-2

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