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JEE Main Mathematics · Class 12

Integral as an antiderivative; fundamental integrals — NEET & JEE Questions

Integral as an antiderivative; fundamental integrals is a topic in Integral Calculus, a Class 12 Mathematics chapter of the JEE Main syllabus. TestBudy holds 6 published JEE Main questions on Integral as an antiderivative; fundamental integrals, each with the marking scheme of the real paper.

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Integral as an antiderivative; fundamental integrals MCQs with solutions

6 of the 6 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L3 · understanding

    Let I(x)=∫dx(x−11)1113(x+15)1513\mathrm{I}(x)=\int \frac{d x}{(x-11)^{\frac{11}{13}}(x+15)^{\frac{15}{13}}}. If I(37)−I(24)=14(1 b113−1c113),b,c∈N\mathrm{I}(37)-\mathrm{I}(24)=\frac{1}{4}\left(\frac{1}{\mathrm{~b}^{\frac{1}{13}}}-\frac{1}{\mathrm{c}^{\frac{1}{13}}}\right), \mathrm{b}, \mathrm{c} \in \mathcal{N}, then 3( b+c)3(\mathrm{~b}+\mathrm{c}) is equal to

    • A. 39
    • B. 22
    • C. 40
    • D. 26
  2. Question 2 · difficulty L3 · understanding

    If ∫1a2sin⁡2x+b2cos⁡2x dx=112tan⁡−1(3tan⁡x)+\int \frac{1}{\mathrm{a}^2 \sin ^2 x+\mathrm{b}^2 \cos ^2 x} \mathrm{~d} x=\frac{1}{12} \tan ^{-1}(3 \tan x)+ constant, then the maximum value of asin⁡x+bcos⁡x\mathrm{a} \sin x+\mathrm{b} \cos x, is :

    • A. 41\sqrt{41}
    • B. 39\sqrt{39}
    • C. 40\sqrt{40}
    • D. 42\sqrt{42}
  3. Question 3 · difficulty L3 · understanding

    For α,β,γ,δ∈N\alpha, \beta, \gamma, \delta \in \mathbb{N}, if ∫((xe)2x+(ex)2x)log⁡exdx=1α(xe)βx−1γ(ex)δx+C\int\left(\left(\frac{x}{e}\right)^{2 x}+\left(\frac{e}{x}\right)^{2 x}\right) \log _{e} x d x=\frac{1}{\alpha}\left(\frac{x}{e}\right)^{\beta x}-\frac{1}{\gamma}\left(\frac{e}{x}\right)^{\delta x}+C , where e=\sum_\limits{n=0}^{\infty} \frac{1}{n !} and C\mathrm{C} is constant of integration, then α+2β+3γ−4δ\alpha+2 \beta+3 \gamma-4 \delta is equal to :

    • A. −8-8
    • B. −4-4
    • C. 1
    • D. 4
  4. Question 4 · difficulty L3 · understanding

    If ∫(x2+1)ex(x+1)2dx=f(x)ex+C\int {{{({x^2} + 1){e^x}} \over {{{(x + 1)}^2}}}dx = f(x){e^x} + C} , where C is a constant, then d3fdx3{{{d^3}f} \over {d{x^3}}} at x = 1 is equal to :

    • A. −34 - {3 \over 4}
    • B. 34{3 \over 4}
    • C. −32 - {3 \over 2}
    • D. 32{3 \over 2}
  5. Question 5 · difficulty L4 · understanding

    The integral ∫[(x2)x+(2x)x]ln⁡(ex2)dx \int\left[\left(\frac{x}{2}\right)^x+\left(\frac{2}{x}\right)^x\right] \ln \left(\frac{e x}{2}\right) d x is equal to :

    • A. (x2)x+(2x)x+C\left(\frac{x}{2}\right)^{x}+\left(\frac{2}{x}\right)^{x}+C
    • B. (x2)x−(2x)x+C\left(\frac{x}{2}\right)^{x}-\left(\frac{2}{x}\right)^{x}+C
    • C. (x2)xlog⁡2(2x)+C\left(\frac{x}{2}\right)^{x} \log _{2}\left(\frac{2}{x}\right)+C
    • D. None
  6. Question 6 · difficulty L4 · understanding

     The integral ∫(1−13)(cos⁡x−sin⁡x)(1+23sin⁡2x)dx is equal to  \text { The integral } \int \frac{\left(1-\frac{1}{\sqrt{3}}\right)(\cos x-\sin x)}{\left(1+\frac{2}{\sqrt{3}} \sin 2 x\right)} d x \text { is equal to }

    • A. 12log⁡e∣tan⁡(x2+π12)tan⁡(x2+π6)∣+C\frac{1}{2} \log _{e}\left|\frac{\tan \left(\frac{x}{2}+\frac{\pi}{12}\right)}{\tan \left(\frac{x}{2}+\frac{\pi}{6}\right)}\right|+C
    • B. 12log⁡e∣tan⁡(x2+π6)tan⁡(x2+π3)∣+C\frac{1}{2} \log _{e}\left|\frac{\tan \left(\frac{x}{2}+\frac{\pi}{6}\right)}{\tan \left(\frac{x}{2}+\frac{\pi}{3}\right)}\right|+C
    • C. log⁡e∣tan⁡(x2+π6)tan⁡(x2+π12)∣+C \log _{e}\left|\frac{\tan \left(\frac{x}{2}+\frac{\pi}{6}\right)}{\tan \left(\frac{x}{2}+\frac{\pi}{12}\right)}\right|+C
    • D. 12log⁡e∣tan⁡(x2−π12)tan⁡(x2−π6)∣+C\frac{1}{2} \log _{e}\left|\frac{\tan \left(\frac{x}{2}-\frac{\pi}{12}\right)}{\tan \left(\frac{x}{2}-\frac{\pi}{6}\right)}\right|+C

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