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JEE Main Mathematics · Class 12

Equation of a line in space — NEET & JEE Questions

Equation of a line in space is a topic in Three Dimensional Geometry, a Class 12 Mathematics chapter of the JEE Main syllabus. TestBudy holds 138 published JEE Main questions on Equation of a line in space, each with the marking scheme of the real paper.

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Equation of a line in space MCQs with solutions

10 of the 138 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L2 · understanding

    r⃗=(i^+j^−k^)+λ(ai^−j^),a≠0\vec{r}=(\hat{i}+\hat{j}-\hat{k})+\lambda(a \hat{i}-\hat{j}), a \neq 0 and r⃗=(4i^−k^)+μ(2i^+ak^)\vec{r}=(4 \hat{i}-\hat{k})+\mu(2 \hat{i}+a \hat{k}) from the origin is :

    • A. 5
    • B. 10
    • C. 17
    • D. 26
  2. Question 2 · difficulty L2 · understanding

    The shortest distance between the lines x−32=y+15−7=z−95\frac{x-3}{2}=\frac{y+15}{-7}=\frac{z-9}{5} and x+12=y−11=z−9−3\frac{x+1}{2}=\frac{y-1}{1}=\frac{z-9}{-3} is

    • A. 838 \sqrt{3}
    • B. 636 \sqrt{3}
    • C. 535 \sqrt{3}
    • D. 434 \sqrt{3}
  3. Question 3 · difficulty L3 · understanding

    Let the foot of perpendicular from the point (λ,2,3)(\lambda, 2,3) on the line x−41=y−92=z−51\frac{x-4}{1}=\frac{y-9}{2}=\frac{z-5}{1} be the point ( 1,μ,21, \mu, 2 ). Then the distance between the lines x−12=y−23=z+46\frac{x-1}{2}=\frac{y-2}{3}=\frac{z+4}{6} and x−λ2=y−μ3=z+56\frac{x-\lambda}{2}=\frac{y-\mu}{3}=\frac{z+5}{6} is equal to :

    • A. 127\frac{12}{7}
    • B. 1457\frac{\sqrt{145}}{7}
    • C. 1467 \frac{\sqrt{146}}{7}
    • D. 1437 \frac{\sqrt{143}}{7}
  4. Question 4 · difficulty L3 · understanding

    Let the image of the point P(1,6,a)\mathrm{P}(1,6, a) in the line L:x1=y−12=z−a+1b,b>0\mathrm{L}: \frac{x}{1}=\frac{y-1}{2}=\frac{z-a+1}{b}, b>0, be (a3,0,a+c)\left(\frac{a}{3}, 0, a+c\right). If S(α,β,γ),α>0\mathrm{S}(\alpha, \beta, \gamma), \alpha>0, is the point on L such that the distance of S from the foot of perpendicular from the point P on L is 2142 \sqrt{14}, then α+β+γ\alpha+\beta+\gamma is equal to:

    • A. 19
    • B. 20
    • C. 21
    • D. 22
  5. Question 5 · difficulty L3 · understanding

    Let a line L be perpendicular to both the lines L1:x+13=y+35=z+57\mathrm{L}_1: \frac{x+1}{3}=\frac{y+3}{5}=\frac{z+5}{7} and L2:x−21=y−44=z−67\mathrm{L}_2: \frac{x-2}{1}=\frac{y-4}{4}=\frac{z-6}{7}. If θ\theta is the acute angle between the lines L and L3:x−872=y−471=z2\mathrm{L}_3: \frac{x-\frac{8}{7}}{2}=\frac{y-\frac{4}{7}}{1}=\frac{z}{2}, then tan⁡θ\tan \theta is equal to:

    • A. 322\frac{3}{2} \sqrt{2}
    • B. 522\frac{5}{2} \sqrt{2}
    • C. 532\frac{5}{3} \sqrt{2}
    • D. 432\frac{4}{3} \sqrt{2}
  6. Question 6 · difficulty L3 · understanding

    Let a triangle PQR be such that P and Q lie on the line x+38=y−42=z+12\frac{x+3}{8}=\frac{y-4}{2}=\frac{z+1}{2} and are at a distance of 6 units from R(1,2,3)R(1,2,3). If (α,β,γ)(\alpha, \beta, \gamma) is the centroid of ΔPQR\Delta P Q R, then α+β+γ\alpha+\beta+\gamma is equal to :

    • A. 4
    • B. 5
    • C. 6
    • D. 8
  7. Question 7 · difficulty L3 · understanding

    The square of the distance of the point P(5,6,7)\mathrm{P}(5,6,7) from the line x−22=y−53=z−24\frac{x-2}{2}=\frac{y-5}{3}=\frac{z-2}{4} is equal to:

    • A. 3
    • B. 5
    • C. 6
    • D. 8
  8. Question 8 · difficulty L3 · understanding

    The shortest distance between the lines r⃗=(13i^+2j^+83k^)+λ(2i^−5j^+6k^) \vec{r}=\left(\frac{1}{3} \hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\frac{8}{3} \hat{\mathrm{k}}\right)+\lambda(2 \hat{\mathrm{i}}-5 \hat{\mathrm{j}}+6 \hat{\mathrm{k}}) and r⃗=(−23i^−13k^)+μ(j^−k^),λ,μ∈R\vec{r}=\left(-\frac{2}{3} \hat{\mathrm{i}}-\frac{1}{3} \hat{\mathrm{k}}\right)+\mu(\hat{\mathrm{j}}-\hat{\mathrm{k}}), \lambda, \mu \in \mathbb{R}, is:

    • A. 5\sqrt{5}
    • B. 3
    • C. 232 \sqrt{3}
    • D. 15\sqrt{15}
  9. Question 9 · difficulty L3 · understanding

    If (2α+1,α2−3α,α−12)\left(2 \alpha+1, \alpha^2-3 \alpha, \frac{\alpha-1}{2}\right) is the image of (α,2α,1)(\alpha, 2 \alpha, 1) in the line x−23=y−12=z1\frac{x-2}{3}=\frac{y-1}{2}=\frac{z}{1}, then the possible value(s) of α\alpha is (are)

    • A. Only 3
    • B. Only 3 and - 1
    • C. Only 3,143, \frac{1}{4} and -1
    • D. Only 3 and 14\frac{1}{4}
  10. Question 10 · difficulty L3 · understanding

    A line with direction ratios 1,−1,21,-1,2 intersects the lines x2=y3=z+13\frac{x}{2}=\frac{y}{3}=\frac{z+1}{3} and x+1−1=y−21=z4\frac{x+1}{-1}=\frac{y-2}{1}=\frac{z}{4} at the points P and Q , respectively. If the length of the line segment PQ is α\alpha, then 225α2225 \alpha^2 is equal to:

    • A. 1024
    • B. 1014
    • C. 1104
    • D. 1204

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