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JEE Main Mathematics · Class 12

Scalar and vector products — NEET & JEE Questions

Scalar and vector products is a topic in Vector Algebra, a Class 12 Mathematics chapter of the JEE Main syllabus. TestBudy holds 195 published JEE Main questions on Scalar and vector products, each with the marking scheme of the real paper.

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Scalar and vector products MCQs with solutions

10 of the 195 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L2 · understanding

    Let a→=2i^+3j^+3k^\overrightarrow{\mathrm{a}}=2 \hat{i}+3 \hat{j}+3 \hat{k} and b→=6i^+3j^+3k^\overrightarrow{\mathrm{b}}=6 \hat{i}+3 \hat{j}+3 \hat{k}. Then the square of the area of the triangle with adjacent sides determined by the vectors (2a⃗+3b⃗)(2 \vec{a}+3 \vec{b}) and (a⃗−b⃗)(\vec{a}-\vec{b}) is :

    • A. 450
    • B. 900
    • C. 1800
    • D. 2400
  2. Question 2 · difficulty L2 · understanding

    Let ∣a⃗∣=2,∣b⃗∣=3|\vec{a}|=2,|\vec{b}|=3 and the angle between the vectors a⃗\vec{a} and b⃗\vec{b} be π4\frac{\pi}{4}. Then ∣(a⃗+2b⃗)×(2a⃗−3b⃗)∣2|(\vec{a}+2 \vec{b}) \times(2 \vec{a}-3 \vec{b})|^{2} is equal to :

    • A. 441
    • B. 482
    • C. 841
    • D. 882
  3. Question 3 · difficulty L2 · understanding

    Let a⃗=5i^−j^−3k^\vec{a}=5 \hat{i}-\hat{j}-3 \hat{k} and b⃗=i^+3j^+5k^\vec{b}=\hat{i}+3 \hat{j}+5 \hat{k} be two vectors. Then which one of the following statements is TRUE ?

    • A. Projection of a⃗\vec{a} on b⃗\vec{b} is −1335\frac{-13}{\sqrt{35}} and the direction of the projection vector is opposite to the direction of b⃗\vec{b}.
    • B. Projection of a⃗\vec{a} on b⃗\vec{b} is 1335\frac{13}{\sqrt{35}} and the direction of the projection vector is opposite to the direction of b⃗\vec{b}.
    • C. Projection of a⃗\vec{a} on b⃗\vec{b} is 1335\frac{13}{\sqrt{35}} and the direction of the projection vector is same as of b⃗\vec{b}.
    • D. Projection of a⃗\vec{a} on b⃗\vec{b} is −1335\frac{-13}{\sqrt{35}} and the direction of the projection vector is same as of b⃗\vec{b}.
  4. Question 4 · difficulty L2 · understanding

    Let a⃗\vec{a} and b⃗\vec{b} be two vectors, Let ∣a⃗∣=1,∣b⃗∣=4|\vec{a}|=1,|\vec{b}|=4 and a⃗⋅b⃗=2\vec{a} \cdot \vec{b}=2. If c⃗=(2a⃗×b⃗)−3b⃗\vec{c}=(2 \vec{a} \times \vec{b})-3 \vec{b}, then the value of b⃗⋅c⃗\vec{b} \cdot \vec{c} is :

    • A. −48-48
    • B. −60-60
    • C. −84-84
    • D. −24-24
  5. Question 5 · difficulty L2 · understanding

    Let a→=i^+j^−k^\overrightarrow a = \widehat i + \widehat j - \widehat k and c→=2i^−3j^+2k^\overrightarrow c = 2\widehat i - 3\widehat j + 2\widehat k. Then the number of vectors b→\overrightarrow b such that b→×c→=a→\overrightarrow b \times \overrightarrow c = \overrightarrow a and ∣b→∣∈|\overrightarrow b | \in {1, 2, ........, 10} is :

    • A. 0
    • B. 1
    • C. 2
    • D. 3
  6. Question 6 · difficulty L2 · understanding

    Let a⃗\vec{a} and b⃗\vec{b} be two vectors such that ∣a⃗∣=14,∣b⃗∣=6|\vec{a}|=\sqrt{14},|\vec{b}|=\sqrt{6} and ∣a⃗×b⃗∣=48|\vec{a} \times \vec{b}|=\sqrt{48}. Then (a⃗⋅b⃗)2(\vec{a} \cdot \vec{b})^{2} is equal to ___________.

  7. Question 7 · difficulty L3 · understanding

    Let a→=4i^−j^+3k^, b→=10i^+2j^−k^\overrightarrow{\mathrm{a}}=4 \hat{i}-\hat{j}+3 \hat{k}, \overrightarrow{\mathrm{~b}}=10 \hat{i}+2 \hat{j}-\hat{k} and a vector c→\overrightarrow{\mathrm{c}} be such that 2(a→×b→)+3( b→×c→)=0→2(\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}})+3(\overrightarrow{\mathrm{~b}} \times \overrightarrow{\mathrm{c}})=\overrightarrow{0}. If a→⋅c→=15\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{c}}=15, then c→⋅(i^+j^−3k^)\overrightarrow{\mathrm{c}} \cdot(\hat{i}+\hat{j}-3 \hat{k}) is equal to :

    • A. -6
    • B. -5
    • C. -4
    • D. -3
  8. Question 8 · difficulty L3 · understanding

    Let a⃗=7i^+j^−k^\vec{a}=\sqrt{7} \hat{i}+\hat{j}-\hat{k} and b⃗=j^+2k^\vec{b}=\hat{j}+2 \hat{k}. If r⃗\vec{r} is a vector such that r⃗×a⃗+a⃗×b⃗=0→\vec{r} \times \vec{a}+\vec{a} \times \vec{b}=\overrightarrow{0} and r⃗⋅a⃗=0\vec{r} \cdot \vec{a}=0, then ∣3r⃗∣2|3 \vec{r}|^2 is equal to:

    • A. 44
    • B. 54
    • C. 86
    • D. 132
  9. Question 9 · difficulty L3 · understanding

    Let u^\hat{u} and v^\hat{v} be unit vectors inclined at an acute angle such that ∣u^×v^∣=32|\hat{u} \times \hat{v}|=\frac{\sqrt{3}}{2}. If A→=λu^+v^+(u^×v^)\overrightarrow{\mathrm{A}}=\lambda \hat{u}+\hat{v}+(\hat{u} \times \hat{v}), then λ\lambda is equal to:

    • A. 43( A→⋅u^)−23( A→⋅v^) \frac{4}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{u})-\frac{2}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{v})
    • B. 23( A→⋅u^)−13( A→⋅v^) \frac{2}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{u})-\frac{1}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{v})
    • C. 43( A→⋅u^)+23( A→⋅v^) \frac{4}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{u})+\frac{2}{3}(\overrightarrow{\mathrm{~A}} \cdot \hat{v})
    • D. (A→⋅u^)−12( A→⋅v^) (\overrightarrow{\mathrm{A}} \cdot \hat{u})-\frac{1}{2}(\overrightarrow{\mathrm{~A}} \cdot \hat{v})
  10. Question 10 · difficulty L3 · understanding

    Let the vectors a⃗=−i^+j^+3k^\vec{a} = -\hat{i} + \hat{j} + 3\hat{k} and b⃗=i^+3j^+k^\vec{b} = \hat{i} + 3\hat{j} + \hat{k}. For some λ,μ∈R\lambda, \mu \in \mathbb{R}, let c⃗=λa⃗+μb⃗\vec{c} = \lambda \vec{a} + \mu \vec{b}. If c⃗⋅(3i^−6j^+2k^)=10\vec{c} \cdot (3\hat{i} - 6\hat{j} + 2\hat{k}) = 10 and c⃗⋅(i^+j^+k^)=−2\vec{c} \cdot (\hat{i} + \hat{j} + \hat{k}) = -2, then ∣c⃗∣2|\vec{c}|^2 is equal to :

    • A. 8
    • B. 12
    • C. 14
    • D. 15

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