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JEE Main Mathematics · Class 11

Probability distribution of a random variable — NEET & JEE Questions

Probability distribution of a random variable is a topic in Statistics and Probability, a Class 11 Mathematics chapter of the JEE Main syllabus. TestBudy holds 30 published JEE Main questions on Probability distribution of a random variable, each with the marking scheme of the real paper.

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Probability distribution of a random variable MCQs with solutions

10 of the 30 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L2 · understanding

    A bag contains 4 white and 6 black balls. Three balls are drawn at random from the bag. Let X\mathrm{X} be the number of white balls, among the drawn balls. If σ2\sigma^{2} is the variance of X\mathrm{X}, then 100σ2100 \sigma^{2} is equal to ________.

  2. Question 2 · difficulty L2 · understanding

    The probability distribution of random variable X is given by : X 1 2 3 4 5 P(X) K 2K 2K 3K K Let p = P(1 < X < 4 | X < 3). If 5p = λ\lambdaK, then λ\lambda equal to ___________.

  3. Question 3 · difficulty L2 · understanding

    The probability distribution of a random variable X is given below : X 4k 307k\frac{30}{7}k 327k\frac{32}{7}k 347k\frac{34}{7}k 367k\frac{36}{7}k 387k\frac{38}{7}k 407k\frac{40}{7}k 6k P(X) 215\frac{2}{15} 115\frac{1}{15} 215\frac{2}{15} 15\frac{1}{5} 115\frac{1}{15} 215\frac{2}{15} 15\frac{1}{5} 115\frac{1}{15} If E(X) = 26315\frac{263}{15}, then P(X < 20) is equal to :

    • A. 35\frac{3}{5}
    • B. 1415\frac{14}{15}
    • C. 815\frac{8}{15}
    • D. 1115\frac{11}{15}
  4. Question 4 · difficulty L2 · understanding

    If a random variable xx has the probability distribution x01234567P(x)02kk3k2k22kk2+k7k2 \begin{array}{|c|c|c|c|c|c|c|c|c|} \hline x & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \hline \mathrm{P}(x) & 0 & 2 \mathrm{k} & \mathrm{k} & 3 \mathrm{k} & 2 \mathrm{k}^2 & 2 \mathrm{k} & \mathrm{k}^2+\mathrm{k} & 7 \mathrm{k}^2 \\ \hline \end{array}  then P(3<x≤6) is equal to  \text { then } \mathrm{P}(3 < x \leq 6) \text { is equal to }

    • A. 0.34
    • B. 0.64
    • C. 0.22
    • D. 0.33
  5. Question 5 · difficulty L2 · understanding

    A random variable X has the following probability distribution : X 0 1 2 3 4 P(X) k 2k 4k 6k 8k The value of P(1 < X < 4 | X ≤\le 2) is equal to :

    • A. 47{4 \over 7}
    • B. 23{2 \over 3}
    • C. 37{3 \over 7}
    • D. 45{4 \over 5}
  6. Question 6 · difficulty L3 · understanding

    Three balls are drawn at random from a bag containing 5 blue and 4 yellow balls. Let the random variables XX and YY respectively denote the number of blue and yellow balls. If Xˉ\bar{X} and Yˉ\bar{Y} are the means of XX and YY respectively, then 7Xˉ+4Yˉ7 \bar{X}+4 \bar{Y} is equal to ___________.

  7. Question 7 · difficulty L3 · understanding

    From a lot of 12 items containing 3 defectives, a sample of 5 items is drawn at random. Let the random variable XX denote the number of defective items in the sample. Let items in the sample be drawn one by one without replacement. If variance of XX is mn\frac{m}{n}, where gcd⁡(m,n)=1\operatorname{gcd}(m, n)=1, then n−mn-m is equal to _________.

  8. Question 8 · difficulty L3 · understanding

    From a lot of 10 items, which include 3 defective items, a sample of 5 items is drawn at random. Let the random variable XX denote the number of defective items in the sample. If the variance of XX is σ2\sigma^2, then 96σ296 \sigma^2 is equal to __________.

  9. Question 9 · difficulty L3 · understanding

    Let the probability of getting head for a biased coin be 14\frac{1}{4}. It is tossed repeatedly until a head appears. Let N\mathrm{N} be the number of tosses required. If the probability that the equation 64x2+5Nx+1=064 \mathrm{x}^{2}+5 \mathrm{Nx}+1=0 has no real root is pq\frac{\mathrm{p}}{\mathrm{q}}, where p\mathrm{p} and q\mathrm{q} are coprime, then q−pq-p is equal to ________.

  10. Question 10 · difficulty L3 · understanding

    The probability distribution of X is : X 0 1 2 3 P(X) 1−d4{{1 - d} \over 4} 1+2d4{{1 + 2d} \over 4} 1−4d4{{1 - 4d} \over 4} 1+3d4{{1 + 3d} \over 4} For the minimum possible value of d, sixty times the mean of X is equal to _______________.

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