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NEET-UG and JEE Main Chemistry · Class 11

First law; internal energy, work and heat — NEET & JEE Questions

First law; internal energy, work and heat is a topic in Chemical Thermodynamics, a Class 11 Chemistry chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 47 published NEET-UG and JEE Main questions on First law; internal energy, work and heat, each with the marking scheme of the real paper.

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First law; internal energy, work and heat MCQs with solutions

10 of the 47 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    Using the chemistry sign convention, the first law of thermodynamics is commonly written as

    • A. ΔU=q+w\Delta U=q+w
    • B. ΔU=q−w\Delta U=q-w always
    • C. ΔU=qw\Delta U=qw
    • D. ΔU=q/w\Delta U=q/w
  2. Question 2 · difficulty L2 · understanding

    A sample of n -octane (1.14 g)(1.14 \mathrm{~g}) was completely burnt in excess of oxygen in a bomb calorimeter, whose heat capacity is 5 kJ K−15 \mathrm{~kJ} \mathrm{~K}^{-1}. As a result of combustion reaction, the temperature of the calorimeter is increased by 5 K . The magnitude of the heat of combustion of octane at constant volume is__________ kJmol−1\mathrm{kJ} \mathrm{mol}^{-1} (nearest integer).

  3. Question 3 · difficulty L2 · understanding

    Three moles of an ideal gas are compressed isothermally from 60 L60 \mathrm{~L} to 20 L20 \mathrm{~L} using constant pressure of 5 atm5 \mathrm{~atm}. Heat exchange Q\mathrm{Q} for the compression is - _________ Lit. atm.

  4. Question 4 · difficulty L2 · understanding

    If 5 moles of an ideal gas expands from 10 L10 \mathrm{~L} to a volume of 100 L100 \mathrm{~L} at 300 K300 \mathrm{~K} under isothermal and reversible condition then work, w\mathrm{w}, is −x J-x \mathrm{~J}. The value of xx is __________. (Given R = 8.314 J K−1^{-1} mol−1^{-1})

  5. Question 5 · difficulty L2 · understanding

    When a 60 W60 \mathrm{~W} electric heater is immersed in a gas for 100 s in a constant volume container with adiabatic walls, the temperature of the gas rises by 5∘C5^{\circ} \mathrm{C}. The heat capacity of the given gas is ___________ JK−1\mathrm{J} \mathrm{K}^{-1} (Nearest integer)

  6. Question 6 · difficulty L2 · understanding

    1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27∘C27^{\circ} \mathrm{C}. The work done is 3 kJ mol−13 \mathrm{~kJ} \mathrm{~mol}^{-1}. The final temperature of the gas is ________ K\mathrm{K} (Nearest integer). Given CV=20 J mol−1 K−1\mathrm{C_V}=20 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}

  7. Question 7 · difficulty L2 · understanding

    When 2 litre of ideal gas expands isothermally into vacuum to a total volume of 6 litre, the change in internal energy is ____________ J. (Nearest integer)

  8. Question 8 · difficulty L2 · understanding

    A gas (Molar mass = 280  g mol−1\mathrm{~g} \mathrm{~mol}^{-1}) was burnt in excess O2\mathrm{O}_{2} in a constant volume calorimeter and during combustion the temperature of calorimeter increased from 298.0 K298.0 \mathrm{~K} to 298.45298.45 K\mathrm{K}. If the heat capacity of calorimeter is 2.5 kJ K−12.5 \mathrm{~kJ} \mathrm{~K}^{-1} and enthalpy of combustion of gas is 9 kJ mol−19 \mathrm{~kJ} \mathrm{~mol}^{-1} then amount of gas burnt is _____________ g. (Nearest Integer)

  9. Question 9 · difficulty L2 · understanding

    4.0 L of an ideal gas is allowed to expand isothermally into vacuum until the total volume is 2.0 L. The amount of heat absorbed in this expansion is ____________ L atm.

  10. Question 10 · difficulty L2 · understanding

    A system does 200 J of work and at the same time absorbs 150 J of heat. The magnitude of the change in internal energy is ____________ J. (Nearest integer)

Common mistakes in First law; internal energy, work and heat

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Subtracts work done on the system.
  • Uses positive signs for heat released and work done by the system.
  • Assumes zero internal-energy change means both heat and work are zero.

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