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NEET-UG and JEE Main Chemistry · Class 11

Group 16 - dioxygen, ozone, sulphur allotropes and sulphuric acid — NEET & JEE Questions

Group 16 - dioxygen, ozone, sulphur allotropes and sulphuric acid is a topic in p-Block Elements, a Class 11 Chemistry chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 50 published NEET-UG and JEE Main questions on Group 16 - dioxygen, ozone, sulphur allotropes and sulphuric acid, each with the marking scheme of the real paper.

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Group 16 - dioxygen, ozone, sulphur allotropes and sulphuric acid MCQs with solutions

10 of the 50 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    Which element belongs to Group 16?

    • A. Oxygen
    • B. Nitrogen
    • C. Chlorine
    • D. Boron
  2. Question 2 · difficulty L2 · understanding

    Given below are two statements : Statement I : The covalency of oxygen is generally two but it can exceed upto four. The oxidation state of oxygen in SO2\mathrm{SO}_2 is -2 and in OF2\mathrm{OF}_2 it is +2 . Statement II : The anomalous behaviour of oxygen when compared to the other elements of group 16 is due to its small size and high electronegativity. In the light of the above statements, choose the correct answer from the options given below

    • A. Both Statement I and Statement II are true
    • B. Both Statement I and Statement II are false
    • C. Statement I is true but Statement II is false
    • D. Statement I is false but Statement II is true
  3. Question 3 · difficulty L2 · understanding

    The large difference between the melting and boiling points of oxygen and sulphur may be explained on the basis of

    • A. Atomicity
    • B. Electron gain enthalpy
    • C. Atomic size
    • D. Electronegativity
  4. Question 4 · difficulty L2 · understanding

    Identify the correct statements about p-block elements and their compounds. (A) Non metals have higher electronegativity than metals. (B) Non metals have lower ionisation enthalpy than metals. (C) Compounds formed between highly reactive nonmetals and highly reactive metals are generally ionic. (D) The non-metal oxides are generally basic in nature. (E) The metal oxides are generally acidic or neutral in nature. Choose the correct answer from the options given below :

    • A. (B) and (D) only
    • B. (B) and (E) only
    • C. (D) and (E) only
    • D. (A) and (C) only
  5. Question 5 · difficulty L2 · understanding

    Given below are two statements: Statement I : S8\mathrm{S}_8 solid undergoes disproportionation reaction under alkaline conditions to form S2−\mathrm{S}^{2-} and S2O32−\mathrm{S}_2 \mathrm{O}_3{ }^{2-}. Statement II : ClO4−\mathrm{ClO}_4^{-} can undergo disproportionation reaction under acidic condition. In the light of the above statements, choose the most appropriate answer from the options given below :

    • A. Statement I is correct but statement II is incorrect
    • B. Both statement I and statement II are incorrect
    • C. Statement I is incorrect but statement II is correct
    • D. Both statement I and statement II are correct
  6. Question 6 · difficulty L2 · understanding

    Which one of the following pairs is an example of polar molecular solids?

    • A. HCl(s),AlN(s)\mathrm{HCl}(\mathrm{s}), \mathrm{AlN}(\mathrm{s})
    • B. MgO(s),SO2(s)\mathrm{MgO}(\mathrm{s}), \mathrm{SO}_{2}(\mathrm{s})
    • C. SO2(s),NH3(s)\mathrm{SO}_{2}(\mathrm{s}), \mathrm{NH}_{3}(\mathrm{s})
    • D. SO2(s),CO2(s)\mathrm{SO}_{2}(\mathrm{s}), \mathrm{CO}_{2}(\mathrm{s})
  7. Question 7 · difficulty L2 · understanding

    K2Cr2O7\mathrm{K_2Cr_2O_7} paper acidified with dilute H2SO4\mathrm{H_2SO_4} turns green when exposed to :

    • A. Sulphur dioxide
    • B. Sulphur trioxide
    • C. Hydrogen sulphide
    • D. Carbon dioxide
  8. Question 8 · difficulty L2 · understanding

    Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Activated charcoal adsorbs SO 2 more efficiently than CH 4 . Reason R : Gases with lower critical temperatures are readily adsorbed by activated charcoal. In the light of the above statements, choose the correct answer from the options given below.

    • A. Both A and R are correct and R is the correct explanation of A.
    • B. Both A and R are correct but R is NOT the correct explanation of A.
    • C. A is correct but R is not correct.
    • D. A is not correct but R is correct.
  9. Question 9 · difficulty L2 · understanding

    The total number of acidic oxides from the following list is NO, N 2 O, B 2 O 3 , N 2 O 5 , CO, SO 3 , P 4 O 10

    • A. 3
    • B. 4
    • C. 5
    • D. 6
  10. Question 10 · difficulty L2 · understanding

    Match List I with List II: List I List II (A) Sulphate (I) Pesticide (B) Fluoride (II) Bending of bones (C) Nicotine (III) Laxative effect (D) Sodium arsinite (IV) Herbicide Choose the correct answer from the options given below :

    • A. A-II, B-III, C-IV, D-I
    • B. A-IV, B-III, C-II, D-I
    • C. A-III, B-II, C-I, D-IV
    • D. A-III, B-II, C-IV, D-I

Common mistakes in Group 16 - dioxygen, ozone, sulphur allotropes and sulphuric acid

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Assumes greater molecular instability means lower chemical reactivity.
  • Assumes monoclinic sulfur is the room-temperature stable form.
  • Confuses dehydrating action with reduction.
  • Treats ozone as both highly reactive and indefinitely stable.

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