Skip to content

NEET-UG and JEE Main Chemistry · Class 12

Phenols - acidity and electrophilic substitution — NEET & JEE Questions

Phenols - acidity and electrophilic substitution is a topic in Organic Compounds Containing Oxygen, a Class 12 Chemistry chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 52 published NEET-UG and JEE Main questions on Phenols - acidity and electrophilic substitution, each with the marking scheme of the real paper.

questions
52
shown here
10
Test me on this topic

Five free tests with an account. Your score comes with the result; where you stand is Pro.

Phenols - acidity and electrophilic substitution MCQs with solutions

10 of the 52 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    Phenol is more acidic than cyclohexanol mainly because

    • A. the phenoxide ion is resonance-stabilised
    • B. phenol has no O-H bond
    • C. cyclohexanol is aromatic
    • D. phenol cannot lose a proton
  2. Question 2 · difficulty L2 · understanding

    What amount of bromine will be required to convert 2 g of phenol into 2,4,6-tribromophenol? (Given molar mass in gmol−1\mathrm{g} \mathrm{mol}^{-1} of C,H,O,Br\mathrm{C}, \mathrm{H}, \mathrm{O}, \mathrm{Br} are 12,1,16,8012,1,16,80 respectively )

    • A. 6.0 g
    • B. 10.22 g
    • C. 20.44 g
    • D. 4.0 g
  3. Question 3 · difficulty L2 · understanding

    Which one the following compounds will readily react with dilute NaOH\mathrm{NaOH} ?

    • A. C6H5CH2OH\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{OH}
    • B. C2H5OH\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}
    • C. C6H5OH\mathrm{C}_6 \mathrm{H}_5 \mathrm{OH}
    • D. (CH3)3COH\left(\mathrm{CH}_3\right)_3 \mathrm{COH}
  4. Question 4 · difficulty L2 · understanding

    Given below are two statement : Statements I : Bromination of phenol in solvent with low polarity such as CHCl3\mathrm{CHCl}_3 or CS2\mathrm{CS}_2 requires Lewis acid catalyst. Statements II : The Lewis acid catalyst polarises the bromine to generate Br+\mathrm{Br}^{+}. In the light of the above statements, choose the correct answer from the options given below :

    • A. Statement I is true but Statement II is false
    • B. Both Statement I and Statement II are true
    • C. Statement I is false but Statement II is true
    • D. Both Statement I and Statement II are false
  5. Question 5 · difficulty L2 · understanding

    Common name of Benzene - 1,2 - diol is -

    • A. catechol
    • B. quinol
    • C. o-cresol
    • D. resorcinol
  6. Question 6 · difficulty L2 · understanding

    Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R: Assertion A: pKa\mathrm{pK}_{\mathrm{a}} value of phenol is 10.0 while that of ethanol is 15.9 . Reason R: Ethanol is stronger acid than phenol. In the light of the above statements, choose the correct answer from the options given below:

    • A. A is false but R is true.
    • B. Both AA and RR are true but RR is NOT the correct explanation of AA.
    • C. Both A\mathrm{A} and R\mathrm{R} are true and R\mathrm{R} is the correct explanation of A\mathrm{A}.
    • D. AA is true but RR is false.
  7. Question 7 · difficulty L2 · understanding

    Phenol treated with chloroform in presence of sodium hydroxide, which further hydrolyzed in presence of an acid results

    • A. Salicylic acid
    • B. Benzene-1,2-diol
    • C. 2-Hydroxybenzaldehyde
    • D. Benzene-1,3-diol
  8. Question 8 · difficulty L2 · understanding

    Match List I with List II List - I (Compound) List - II (pKa\mathrm{pK_a} value) (A) Ethanol (I) 10.0 (B) Phenol (II) 15.9 (C) m-Nitrophenol (III) 7.1 (D) p-Nitrophenol (IV) 8.3 Choose the correct answer from the options given below:

    • A. A-I, B-II, C-III, D-IV
    • B. A-IV, B-I, C-II, D-III
    • C. A-II, B-I, C-IV, D-III
    • D. A-III, B-IV, C-I, D-II
  9. Question 9 · difficulty L2 · understanding

    Phenolic group can be identified by a positive:

    • A. Tollen's test
    • B. Phthalein dye test
    • C. Carbylamine test
    • D. Lucas test
  10. Question 10 · difficulty L2 · understanding

    Given below are two statements : Statement (I) : p-nitrophenol is more acidic than m-nitrophenol and o-nitrophenol. Statement (II) : Ethanol will give immediate turbidity with Lucas reagent. In the light of the above statements, choose the correct answer from the options given below :

    • A. Statement I is true but Statement II is false
    • B. Both Statement I and Statement II are true
    • C. Both Statement I and Statement II are false
    • D. Statement I is false but Statement II is true

Common mistakes in Phenols - acidity and electrophilic substitution

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Reverses the electronic effect of the nitro group.

Practise this chapter

Reading a question and answering it under a clock are different things. A chapter-length test measures whether the topic went in.