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NEET-UG and JEE Main Physics · Class 11

Static, kinetic and rolling friction — NEET & JEE Questions

Static, kinetic and rolling friction is a topic in Laws of Motion, a Class 11 Physics chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 44 published NEET-UG and JEE Main questions on Static, kinetic and rolling friction, each with the marking scheme of the real paper.

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Static, kinetic and rolling friction MCQs with solutions

10 of the 44 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    Static friction on a surface

    • A. adjusts up to a limiting value before slipping begins
    • B. always equals μsN\mu_sN
    • C. is always zero
    • D. acts only after sliding starts
  2. Question 2 · difficulty L2 · understanding

    An inclined plane is bent in such a way that the vertical cross-section is given by y=x24y = {{{x^2}} \over 4} where y is in vertical and x in horizontal direction. If the upper surface of this curved plane is rough with coefficient of friction μ\mu = 0.5, the maximum height in cm at which a stationary block will not slip downward is _________ cm.

  3. Question 3 · difficulty L2 · understanding

    The coefficient of static friction between a wooden block of mass 0.5 kg and a vertical rough wall is 0.2. The magnitude of horizontal force that should be applied on the block to keep it adhere to the wall will be _________ N. [g = 10 ms −-2 ]

  4. Question 4 · difficulty L2 · understanding

    A block is sliding down on an inclined plane of slope θ\theta and at an instant t=0t=0 this block is given an upward momentum so that it starts moving up on the inclined surface with velocity uu. The distance (S)(S) travelled by the block before its velocity become zero, is ____\_\_\_\_ . (g = gravitational acceleration)

    • A. 2u2 gcos⁡θ\frac{2 u^2}{\mathrm{~g} \cos \theta}
    • B. u22gcos⁡θ\frac{u^2}{\sqrt{2} g \cos \theta}
    • C. u22gsin⁡θ\frac{u^2}{2 g \sin \theta}
    • D. u22gcos⁡θ\frac{u^2}{2 g \cos \theta}
  5. Question 5 · difficulty L2 · understanding

    A cubic block of mass mm is sliding down on an inclined plane at 60∘60^{\circ} with an acceleration of g2\frac{g}{2}, the value of coefficient of kinetic friction is

    • A. 32\frac{\sqrt{3}}{2}
    • B. 23\frac{\sqrt{2}}{3}
    • C. 1−321-\frac{\sqrt{3}}{2}
    • D. 3−1\sqrt{3}-1
  6. Question 6 · difficulty L2 · understanding

    A heavy box of mass 50 kg50 \mathrm{~kg} is moving on a horizontal surface. If co-efficient of kinetic friction between the box and horizontal surface is 0.3 then force of kinetic friction is :

    • A. 1470 N
    • B. 147 N
    • C. 1.47 N
    • D. 14.7 N
  7. Question 7 · difficulty L2 · understanding

    A 2 kg2 \mathrm{~kg} brick begins to slide over a surface which is inclined at an angle of 45∘45^{\circ} with respect to horizontal axis. The co-efficient of static friction between their surfaces is:

    • A. 1
    • B. 1.7
    • C. 0.5
    • D. 13\frac{1}{\sqrt{3}}
  8. Question 8 · difficulty L2 · understanding

    Given below are two statements : Statement (I) : The limiting force of static friction depends on the area of contact and independent of materials. Statement (II) : The limiting force of kinetic friction is independent of the area of contact and depends on materials. In the light of the above statements, choose the most appropriate answer from the options given below :

    • A. Statement I is incorrect but Statement II is correct
    • B. Both Statement I and Statement II are correct
    • C. Both Statement I and Statement II are incorrect
    • D. Statement I is correct but Statement II is incorrect
  9. Question 9 · difficulty L2 · understanding

    A block of mass 5 kg5 \mathrm{~kg} is placed at rest on a table of rough surface. Now, if a force of 30 N30 \mathrm{~N} is applied in the direction parallel to surface of the table, the block slides through a distance of 50 m50 \mathrm{~m} in an interval of time 10 s10 \mathrm{~s}. Coefficient of kinetic friction is (given, g=10 ms−2g=10 \mathrm{~ms}^{-2}):

    • A. 0.25
    • B. 0.75
    • C. 0.60
    • D. 0.50
  10. Question 10 · difficulty L2 · understanding

    A body of mass 10 kg10 \mathrm{~kg} is moving with an initial speed of 20 m/s20 \mathrm{~m} / \mathrm{s}. The body stops after 5 s5 \mathrm{~s} due to friction between body and the floor. The value of the coefficient of friction is: (Take acceleration due to gravity g=10 ms−2g=10 \mathrm{~ms}^{-2} )

    • A. 0.3
    • B. 0.2
    • C. 0.5
    • D. 0.4

Common mistakes in Static, kinetic and rolling friction

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Uses mass instead of normal force in the friction formula.
  • Uses the static coefficient formula or multiplies by mass instead of normal force.
  • Assumes rolling friction is exactly zero.
  • Assumes friction must equal the applied force even after sliding begins.

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