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NEET-UG and JEE Main Physics · Class 11

Bernoulli's principle and its applications — NEET & JEE Questions

Bernoulli's principle and its applications is a topic in Properties of Solids and Liquids, a Class 11 Physics chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 12 published NEET-UG and JEE Main questions on Bernoulli's principle and its applications, each with the marking scheme of the real paper.

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Bernoulli's principle and its applications MCQs with solutions

10 of the 12 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    For steady flow of an incompressible, non-viscous fluid along a streamline, which expression remains constant according to Bernoulli's principle?

    • A. P+12ρv2+ρghP + \frac{1}{2}\rho v^2 + \rho gh
    • B. P+ρv2+ρghP + \rho v^2 + \rho gh
    • C. P−12ρv2+ρghP - \frac{1}{2}\rho v^2 + \rho gh
    • D. P+ρghP + \rho gh
  2. Question 2 · difficulty L2 · understanding

    Water flows steadily through a horizontal pipe that becomes narrower. Which change occurs as the water enters the narrower section?

    • A. Speed decreases and pressure increases
    • B. Speed increases and pressure decreases
    • C. Both speed and pressure increase
    • D. Both speed and pressure remain unchanged
  3. Question 3 · difficulty L2 · understanding

    A small hole is made in the side of a large open tank at a depth hh below the water surface. Neglecting viscosity, what happens to the speed of efflux if the depth of the hole is increased from hh to 4h4h?

    • A. It becomes four times
    • B. It becomes twice
    • C. It becomes one-half
    • D. It remains unchanged
  4. Question 4 · difficulty L2 · understanding

    In a perfume atomizer, fast-moving air is blown across the mouth of a vertical tube dipping into the liquid. Why does the liquid rise in the tube?

    • A. The fast air increases the pressure above the tube and pushes the liquid downward
    • B. The fast air lowers the pressure at the tube mouth, so the higher pressure on the liquid surface pushes the liquid upward
    • C. The liquid rises because its density decreases when air moves over it
    • D. The moving air pulls the liquid upward only by viscous friction
  5. Question 5 · difficulty L3 · application

    Water flows through a horizontal pipe. At section 1, the cross-sectional area is 4 cm24\,\text{cm}^2, the speed is 2 m s−12\,\text{m s}^{-1} and the pressure is 1.50×105 Pa1.50\times10^5\,\text{Pa}. At section 2, the area is 2 cm22\,\text{cm}^2. Taking the density of water as 1000 kg m−31000\,\text{kg m}^{-3}, what is the pressure at section 2?

    • A. 1.38×105 Pa1.38\times10^5\,\text{Pa}
    • B. 1.44×105 Pa1.44\times10^5\,\text{Pa}
    • C. 1.49×105 Pa1.49\times10^5\,\text{Pa}
    • D. 1.56×105 Pa1.56\times10^5\,\text{Pa}
  6. Question 6 · difficulty L3 · application

    A large open tank contains water. A small hole is located 5 m5\,\text{m} below the free surface. Neglecting viscosity and taking g=10 m s−2g=10\,\text{m s}^{-2}, what is the speed of water emerging from the hole?

    • A. 5 m s−15\,\text{m s}^{-1}
    • B. 10 m s−110\,\text{m s}^{-1}
    • C. 25 m s−125\,\text{m s}^{-1}
    • D. 100 m s−1100\,\text{m s}^{-1}
  7. Question 7 · difficulty L3 · application

    A horizontal Venturi tube carries water. The diameters of its wider and narrower sections are 4 cm4\,\text{cm} and 2 cm2\,\text{cm} respectively. If the speed in the wider section is 1 m s−11\,\text{m s}^{-1}, what is the pressure difference between the wider and narrower sections? Take ρ=1000 kg m−3\rho=1000\,\text{kg m}^{-3}.

    • A. 1.5 kPa1.5\,\text{kPa}
    • B. 7.5 kPa7.5\,\text{kPa}
    • C. 15 kPa15\,\text{kPa}
    • D. 30 kPa30\,\text{kPa}
  8. Question 8 · difficulty L3 · application

    A Pitot tube measures the speed of air. The stagnation pressure exceeds the static pressure by 800 Pa800\,\text{Pa}. If the air density is 1.25 kg m−31.25\,\text{kg m}^{-3}, what is the air speed?

    • A. 25 m s−125\,\text{m s}^{-1}
    • B. 36 m s−136\,\text{m s}^{-1}
    • C. 45 m s−145\,\text{m s}^{-1}
    • D. 1280 m s−11280\,\text{m s}^{-1}
  9. Question 9 · difficulty L4 · application

    Water flows steadily upward through a pipe. At a lower section, the area is AA, speed is 3 m s−13\,\text{m s}^{-1} and pressure is 2.50×105 Pa2.50\times10^5\,\text{Pa}. At a point 4 m4\,\text{m} higher, the area is A/2A/2. Taking ρ=1000 kg m−3\rho=1000\,\text{kg m}^{-3} and g=10 m s−2g=10\,\text{m s}^{-2}, what is the pressure at the upper point?

    • A. 1.965×105 Pa1.965\times10^5\,\text{Pa}
    • B. 2.235×105 Pa2.235\times10^5\,\text{Pa}
    • C. 2.10×105 Pa2.10\times10^5\,\text{Pa}
    • D. 2.365×105 Pa2.365\times10^5\,\text{Pa}
  10. Question 10 · difficulty L4 · application

    The water surface in a large tank is 20 m20\,\text{m} above the ground. A small hole in the vertical side ejects water horizontally. At what height above the ground should the hole be made so that the horizontal range of the water jet is maximum?

    • A. 5 m5\,\text{m}
    • B. 10 m10\,\text{m}
    • C. 15 m15\,\text{m}
    • D. 20 m20\,\text{m}

Common mistakes in Bernoulli's principle and its applications

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Calculates the siphon speed but ignores the additional pressure decrease caused by the crest being above the reservoir surface.
  • Uses the required area ratio directly as the diameter ratio instead of taking its square root.

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