NEET-UG and JEE Main Physics · Class 11
Second law; reversible and irreversible processes — NEET & JEE Questions
Second law; reversible and irreversible processes is a topic in Thermodynamics, a Class 11 Physics chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 33 published NEET-UG and JEE Main questions on Second law; reversible and irreversible processes, each with the marking scheme of the real paper.
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Second law; reversible and irreversible processes MCQs with solutions
10 of the 33 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.
The second law of thermodynamics implies that the entropy of an isolated system
- A. cannot decrease in a spontaneous process
- B. must always decrease
- C. is always zero
- D. is unrelated to irreversibility
The difference of temperature in a material can convert heat energy into electrical energy. To harvest the heat energy, the material should have
- A. low thermal conductivity and high electrical conductivity
- B. low thermal conductivity and low electrical conductivity
- C. high thermal conductivity and high electrical conductivity
- D. high thermal conductivity and low electrical conductivity
An engine operating between the boiling and freezing points of water will have A. efficiency more than 27%. B. efficiency less than the efficiency of a Carnot engine operating between the same two temperatures. C. efficiency equal to D. efficiency less than Choose the correct answer from the options given below:
- A. B and C only
- B. B and D only
- C. B, C and D only
- D. A and B only
Work done by a Carnot engine operating between temperatures and is . The amount of heat transferred to the engine by the reservoir is :
- A. 8 kJ
- B. 2 kJ
- C. 4 kJ
- D. 2.67 kJ
A Carnot engine operating between two reservoirs has efficiency . When the temperature of cold reservoir raised by x, its efficiency decreases to . The value of x, if the temperature of hot reservoir is C, will be :
- A. 66 K
- B. 62 K
- C. 16.5 K
- D. 33 K
Given below are two statements: one is labelled as Assertion and the other is labelled as Reason Assertion A : Efficiency of a reversible heat engine will be highest at temperature of cold reservoir. Reason R : The efficiency of Carnot's engine depends not only on the temperature of the cold reservoir but it depends on the temperature of the hot reservoir too and is given as In the light of the above statements, choose the correct answer from the options given below
- A. Both and are true and is the correct explanation of
- B. Both and are true but is NOT the correct explanation of
- C. A is false but is true
- D. A is true but is false
Let is the efficiency of an engine at and while is the efficiency at and The ratio will be :
- A. 0.41
- B. 0.56
- C. 0.73
- D. 0.70
The efficiency of a Carnot's engine, working between steam point and ice point, will be :
- A. 26.81%
- B. 37.81%
- C. 47.81%
- D. 57.81%
A Carnot engine whose heat sinks at 27C, has an efficiency of 25%. By how many degrees should the temperature of the source be changed to increase the efficiency by 100% of the original efficiency?
- A. Increases by 18C
- B. Increases by 200C
- C. Increases by 120C
- D. Increases by 73C
An ideal gas in a cylinder is separated by a piston in such a way that the entropy of one part is S 1 and that of the other part is S 2 . Given that S 1 > S 2 . If the piston is removed then the total entropy of the system will be :
- A. S 1 S 2
- B.
- C. S 1 S 2
- D. S 1 + S 2
Common mistakes in Second law; reversible and irreversible processes
Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.
- Equates any slow process with reversibility without considering dissipation.
- Assumes zero work makes a process reversible.
- Uses the first law alone and overlooks the second-law restriction.
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