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NEET-UG and JEE Main Physics · Class 11

Second law; reversible and irreversible processes — NEET & JEE Questions

Second law; reversible and irreversible processes is a topic in Thermodynamics, a Class 11 Physics chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 33 published NEET-UG and JEE Main questions on Second law; reversible and irreversible processes, each with the marking scheme of the real paper.

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Second law; reversible and irreversible processes MCQs with solutions

10 of the 33 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    The second law of thermodynamics implies that the entropy of an isolated system

    • A. cannot decrease in a spontaneous process
    • B. must always decrease
    • C. is always zero
    • D. is unrelated to irreversibility
  2. Question 2 · difficulty L2 · understanding

    The difference of temperature in a material can convert heat energy into electrical energy. To harvest the heat energy, the material should have

    • A. low thermal conductivity and high electrical conductivity
    • B. low thermal conductivity and low electrical conductivity
    • C. high thermal conductivity and high electrical conductivity
    • D. high thermal conductivity and low electrical conductivity
  3. Question 3 · difficulty L2 · understanding

    An engine operating between the boiling and freezing points of water will have A. efficiency more than 27%. B. efficiency less than the efficiency of a Carnot engine operating between the same two temperatures. C. efficiency equal to 27%27 \% D. efficiency less than 27%27 \% Choose the correct answer from the options given below:

    • A. B and C only
    • B. B and D only
    • C. B, C and D only
    • D. A and B only
  4. Question 4 · difficulty L2 · understanding

    Work done by a Carnot engine operating between temperatures 127∘C127^{\circ} \mathrm{C} and 27∘C27^{\circ} \mathrm{C} is 2 kJ2 \mathrm{~kJ}. The amount of heat transferred to the engine by the reservoir is :

    • A. 8 kJ
    • B. 2 kJ
    • C. 4 kJ
    • D. 2.67 kJ
  5. Question 5 · difficulty L2 · understanding

    A Carnot engine operating between two reservoirs has efficiency 13\frac{1}{3}. When the temperature of cold reservoir raised by x, its efficiency decreases to 16\frac{1}{6}. The value of x, if the temperature of hot reservoir is 99∘99^\circC, will be :

    • A. 66 K
    • B. 62 K
    • C. 16.5 K
    • D. 33 K
  6. Question 6 · difficulty L2 · understanding

    Given below are two statements: one is labelled as Assertion A\mathbf{A} and the other is labelled as Reason R\mathbf{R} Assertion A : Efficiency of a reversible heat engine will be highest at −273∘C-273^{\circ} \mathrm{C} temperature of cold reservoir. Reason R : The efficiency of Carnot's engine depends not only on the temperature of the cold reservoir but it depends on the temperature of the hot reservoir too and is given as η=(1−T2T1)\eta=\left(1-\frac{T_{2}}{T_{1}}\right) In the light of the above statements, choose the correct answer from the options given below

    • A. Both A\mathbf{A} and R\mathbf{R} are true and R\mathbf{R} is the correct explanation of A\mathbf{A}
    • B. Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is NOT the correct explanation of A\mathbf{A}
    • C. A is false but R\mathbf{R} is true
    • D. A is true but R\mathbf{R} is false
  7. Question 7 · difficulty L2 · understanding

    Let η1\eta_{1} is the efficiency of an engine at T1=447∘CT_{1}=447^{\circ} \mathrm{C} and T2=147∘C\mathrm{T}_{2}=147^{\circ} \mathrm{C} while η2\eta_{2} is the efficiency at T1=947∘C\mathrm{T}_{1}=947^{\circ} \mathrm{C} and T2=47∘C\mathrm{T}_{2}=47^{\circ} \mathrm{C} The ratio η1η2\frac{\eta_{1}}{\eta_{2}} will be :

    • A. 0.41
    • B. 0.56
    • C. 0.73
    • D. 0.70
  8. Question 8 · difficulty L2 · understanding

    The efficiency of a Carnot's engine, working between steam point and ice point, will be :

    • A. 26.81%
    • B. 37.81%
    • C. 47.81%
    • D. 57.81%
  9. Question 9 · difficulty L2 · understanding

    A Carnot engine whose heat sinks at 27∘^\circC, has an efficiency of 25%. By how many degrees should the temperature of the source be changed to increase the efficiency by 100% of the original efficiency?

    • A. Increases by 18∘^\circC
    • B. Increases by 200∘^\circC
    • C. Increases by 120∘^\circC
    • D. Increases by 73∘^\circC
  10. Question 10 · difficulty L2 · understanding

    An ideal gas in a cylinder is separated by a piston in such a way that the entropy of one part is S 1 and that of the other part is S 2 . Given that S 1 > S 2 . If the piston is removed then the total entropy of the system will be :

    • A. S 1 −- S 2
    • B. S1S2{{{S_1}} \over {{S_2}}}
    • C. S 1 ×\times S 2
    • D. S 1 + S 2

Common mistakes in Second law; reversible and irreversible processes

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Equates any slow process with reversibility without considering dissipation.
  • Assumes zero work makes a process reversible.
  • Uses the first law alone and overlooks the second-law restriction.

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