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NEET-UG and JEE Main Physics · Class 12

Electric field and electric field lines — NEET & JEE Questions

Electric field and electric field lines is a topic in Electrostatics, a Class 12 Physics chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 41 published NEET-UG and JEE Main questions on Electric field and electric field lines, each with the marking scheme of the real paper.

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Electric field and electric field lines MCQs with solutions

10 of the 41 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    Electric field at a point is defined as the force experienced per unit

    • A. positive test charge
    • B. mass
    • C. negative source charge only
    • D. potential energy
  2. Question 2 · difficulty L2 · understanding

    A stream of a positively charged particles having qm=2×1011Ckg{q \over m} = 2 \times {10^{11}}{C \over {kg}} and velocity v→0=3×107i^ m/s{\overrightarrow v _0} = 3 \times {10^7}\widehat i\,m/s is deflected by an electric field 1.8j^1.8\widehat j kV/m. The electric field exists in a region of 10 cm along xx direction. Due to the electric field, the deflection of the charge particles in the yy direction is _________ mm.

  3. Question 3 · difficulty L2 · understanding

    A long cylindrical volume contains a uniformly distributed charge of density ρ Cm−3\rho \,\mathrm{Cm}^{-3}. The electric field inside the cylindrical volume at a distance x=2ε0ρmx=\frac{2 \varepsilon_{0}}{\rho} \mathrm{m} from its axis is ________ Vm−1\mathrm{Vm}^{-1}.

  4. Question 4 · difficulty L2 · understanding

    A thin half ring of radius 35 cm is uniformly charged with a total charge of QQ coulomb. If the magnitude of the electric field at centre of the half ring is 100 V/m100 \mathrm{~V} / \mathrm{m}, then the value of QQ is ____\_\_\_\_ nC . (ϵ0=8.85×10−12C2/Nm2 and π=3.14) \left(\epsilon_0=8.85 \times 10^{-12} \mathrm{C}^2 / \mathrm{Nm}^2 \text { and } \pi=3.14\right)

    • A. 2.14
    • B. 2.44
    • C. 3.25
    • D. 0.7
  5. Question 5 · difficulty L2 · understanding

    A point charge +q+q is placed at the origin. A second point charge +9q+9 q is placed at (d,0,0\mathrm{d}, 0,0) in Cartesian coordinate system. The point in between them where the electric field vanishes is:

    • A. (3d/4,0,0)(3 \mathrm{d} / 4,0,0)
    • B. (d/4,0,0)(\mathrm{d} / 4,0,0)
    • C. (4d/3,0,0)(4 \mathrm{d} / 3,0,0)
    • D. (d/3,0,0)(\mathrm{d} / 3,0,0)
  6. Question 6 · difficulty L2 · understanding

    Two charges qq and 3q3 q are separated by a distance 'rr' in air. At a distance xx from charge qq, the resultant electric field is zero. The value of xx is :

    • A. r3(1+3)\frac{r}{3(1+\sqrt{3})}
    • B. (1+3)r\frac{(1+\sqrt{3})}{r}
    • C. r(1+3)\frac{r}{(1+\sqrt{3})}
    • D. r(1+3)r(1+\sqrt{3})
  7. Question 7 · difficulty L2 · understanding

    Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : Work done by electric field on moving a positive charge on an equipotential surface is always zero. Reason (R) : Electric lines of forces are always perpendicular to equipotential surfaces. In the light of the above statements, choose the most appropriate answer from the options given below :

    • A. Both (A) and (R) are correct and (R) is the correct explanation of (A)
    • B. (A) is correct but (R) is not correct
    • C. Both (A) and (R) are correct but (R) is not the correct explanation of (A)
    • D. (A) is not correct but (R) is correct
  8. Question 8 · difficulty L2 · understanding

    In a metallic conductor, under the effect of applied electric field, the free electrons of the conductor

    • A. move in the straight line paths in the same direction
    • B. move with the uniform velocity throughout from lower potential to higher potential
    • C. drift from higher potential to lower potential.
    • D. move in the curved paths from lower potential to higher potential
  9. Question 9 · difficulty L2 · understanding

    Electric field in a certain region is given by E→=(Ax2i^+By3j^). The SI unit of A and B\overrightarrow{\mathrm{E}}=\left(\frac{\mathrm{A}}{x^{2}} \hat{i}+\frac{\mathrm{B}}{y^{3}} \hat{j}\right) \text {. The } \mathrm{SI} \text { unit of } \mathrm{A} \text { and } \mathrm{B} are :

    • A. Nm2C;Nm3C\mathrm{Nm}^{2} \mathrm{C} ; \mathrm{Nm}^{3} \mathrm{C}
    • B. Nm3C−1;Nm2C−1\mathrm{Nm}^{3} \mathrm{C}^{-1} ; \mathrm{Nm}^{2} \mathrm{C}^{-1}
    • C. Nm3C;Nm2C\mathrm{Nm}^{3} \mathrm{C} ; \mathrm{Nm}^{2} \mathrm{C}
    • D. Nm2C−1;Nm3C−1\mathrm{Nm}^{2} \mathrm{C}^{-1} ; \mathrm{Nm}^{3} \mathrm{C}^{-1}
  10. Question 10 · difficulty L2 · understanding

    A point charge 2×10−2 C2\times10^{-2}~\mathrm{C} is moved from P to S in a uniform electric field of 30 NC−130~\mathrm{NC^{-1}} directed along positive x-axis. If coordinates of P and S are (1, 2, 0) m and (0, 0, 0) m respectively, the work done by electric field will be

    • A. 600 mJ
    • B. −1200-1200 mJ
    • C. 1200 mJ
    • D. −600-600 mJ

Common mistakes in Electric field and electric field lines

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Treats field lines as material paths that may intersect.

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