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JEE Main Mathematics · Class 11

Modulus and argument of a complex number — NEET & JEE Questions

Modulus and argument of a complex number is a topic in Complex Numbers and Quadratic Equations, a Class 11 Mathematics chapter of the JEE Main syllabus. TestBudy holds 41 published JEE Main questions on Modulus and argument of a complex number, each with the marking scheme of the real paper.

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Modulus and argument of a complex number MCQs with solutions

10 of the 41 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L2 · understanding

    Let z1z_1 and z2z_2 be two distinct complex numbers let z=(1−t)z1+tz2z=(1-t) z_1+t z_2 for some real number t with 0<t<10 < t < 1. If Arg⁡(w)\operatorname{Arg}(w) denotes the principal argument of a nonzero complex number ww, then :

    • A. ∣z−z1∣+∣z−z2∣=∣z1−z2∣\left|z-z_1\right|+\left|z-z_2\right|=\left|z_1-z_2\right|
    • B. Arg⁡(z−z1)=Arg⁡(z−z2)\operatorname{Arg}\left(z-z_1\right)=\operatorname{Arg}\left(z-z_2\right)
    • C. $\left|z−z1zˉ−zˉ1z2−z1zˉ2−zˉ1\begin{array}{cc}z-z_1 & \bar{z}-\bar{z}_1 \\ z_2-z_1 & \bar{z}_2-\bar{z}_1\end{array}\right|=0$
    • D. Arg⁡(z−z1)=Arg⁡(z2−z1)\operatorname{Arg}\left(z-z_1\right)=\operatorname{Arg}\left(z_2-z_1\right)
  2. Question 2 · difficulty L3 · understanding

    Let S={z∈C:z2+4z+16=0}\mathrm{S}=\left\{z \in \mathrm{C}: z^2+4 z+16=0\right\}. Then ∑z∈ S∣z+3i∣2\sum\limits_{z \in \mathrm{~S}}|z+\sqrt{3} \mathrm{i}|^2 is equal to :

    • A. 42
    • B. 23
    • C. 27
    • D. 38
  3. Question 3 · difficulty L3 · understanding

    Let zz be the complex number satisfying ∣z−5∣≤3|z-5| \leq 3 and having maximum positive principal argument. Then 34∣5z−125iz+16∣234 \left| \frac{5z - 12}{5iz + 16} \right|^2 is equal to:

    • A. 20
    • B. 26
    • C. 12
    • D. 16
  4. Question 4 · difficulty L3 · understanding

    If z1,z2z_1, z_2 are two distinct complex number such that ∣z1−2z212−z1zˉ2∣=2\left|\frac{z_1-2 z_2}{\frac{1}{2}-z_1 \bar{z}_2}\right|=2, then

    • A. either z1z_1 lies on a circle of radius 12\frac{1}{2} or z2z_2 lies on a circle of radius 1.
    • B. z1z_1 lies on a circle of radius 12\frac{1}{2} and z2z_2 lies on a circle of radius 1.
    • C. either z1z_1 lies on a circle of radius 1 or z2z_2 lies on a circle of radius 12\frac{1}{2}.
    • D. both z1z_1 and z2z_2 lie on the same circle.
  5. Question 5 · difficulty L3 · understanding

    Consider the following two statements : Statement I: For any two non-zero complex numbers z1,z2,(∣z1∣+∣z2∣)∣z1∣z1∣+z2∣z2∣∣≤2(∣z1∣+∣z2∣), and z_1, z_2,(|z_1|+|z_2|)\left|\frac{z_1}{\left|z_1\right|}+\frac{z_2}{\left|z_2\right|}\right| \leq 2\left(\left|z_1\right|+\left|z_2\right|\right) \text {, and } Statement II : If x,y,zx, y, z are three distinct complex numbers and a,b,c\mathrm{a}, \mathrm{b}, \mathrm{c} are three positive real numbers such that a∣y−z∣=b∣z−x∣=c∣x−y∣\frac{\mathrm{a}}{|y-z|}=\frac{\mathrm{b}}{|z-x|}=\frac{\mathrm{c}}{|x-y|}, then a2y−z+b2z−x+c2x−y=1\frac{\mathrm{a}^2}{y-z}+\frac{\mathrm{b}^2}{z-x}+\frac{\mathrm{c}^2}{x-y}=1. Between the above two statements,

    • A. both Statement I and Statement II are incorrect.
    • B. Statement I is correct but Statement II is incorrect.
    • C. Statement I is incorrect but Statement II is correct.
    • D. both Statement I and Statement II are correct.
  6. Question 6 · difficulty L3 · understanding

    If zz is a complex number such that ∣z∣⩽1|z| \leqslant 1, then the minimum value of ∣z+12(3+4i)∣\left|z+\frac{1}{2}(3+4 i)\right| is :

    • A. 2
    • B. 52\frac{5}{2}
    • C. 32\frac{3}{2}
    • D. 3
  7. Question 7 · difficulty L3 · understanding

    Let r\mathrm{r} and θ\theta respectively be the modulus and amplitude of the complex number z=2−i(2tan⁡5π8)z=2-i\left(2 \tan \frac{5 \pi}{8}\right), then (r,θ)(\mathrm{r}, \theta) is equal to

    • A. (2sec⁡11π8,11π8)\left(2 \sec \frac{11 \pi}{8}, \frac{11 \pi}{8}\right)
    • B. (2sec⁡3π8,3π8)\left(2 \sec \frac{3 \pi}{8}, \frac{3 \pi}{8}\right)
    • C. (2sec⁡5π8,3π8)\left(2 \sec \frac{5 \pi}{8}, \frac{3 \pi}{8}\right)
    • D. (2sec⁡3π8,5π8)\left(2 \sec \frac{3 \pi}{8}, \frac{5 \pi}{8}\right)
  8. Question 8 · difficulty L3 · understanding

    Let w1w_{1} be the point obtained by the rotation of z1=5+4iz_{1}=5+4 i about the origin through a right angle in the anticlockwise direction, and w2w_{2} be the point obtained by the rotation of z2=3+5iz_{2}=3+5 i about the origin through a right angle in the clockwise direction. Then the principal argument of w1−w2w_{1}-w_{2} is equal to :

    • A. −π+tan⁡−189-\pi+\tan ^{-1} \frac{8}{9}
    • B. −π+tan⁡−1335-\pi+\tan ^{-1} \frac{33}{5}
    • C. π−tan⁡−189\pi-\tan ^{-1} \frac{8}{9}
    • D. π−tan⁡−1335\pi-\tan ^{-1} \frac{33}{5}
  9. Question 9 · difficulty L3 · understanding

    If for z=α+iβ,∣z+2∣=z+4(1+i)z=\alpha+i \beta,|z+2|=z+4(1+i), then α+β\alpha+\beta and αβ\alpha \beta are the roots of the equation :

    • A. x2+2x−3=0x^{2}+2 x-3=0
    • B. x2+3x−4=0x^{2}+3 x-4=0
    • C. x2+x−12=0x^{2}+x-12=0
    • D. x2+7x+12=0x^{2}+7 x+12=0
  10. Question 10 · difficulty L3 · understanding

    Let zz be a complex number such that ∣z−2iz+i∣=2,z≠−i\left| {{{z - 2i} \over {z + i}}} \right| = 2,z \ne - i. Then zz lies on the circle of radius 2 and centre :

    • A. (0, −-2)
    • B. (0, 0)
    • C. (0, 2)
    • D. (2, 0)

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