NEET-UG and JEE Main Chemistry · Class 11
Percentage composition; empirical and molecular formulae — NEET & JEE Questions
Percentage composition; empirical and molecular formulae is a topic in Some Basic Concepts in Chemistry, a Class 11 Chemistry chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 12 published NEET-UG and JEE Main questions on Percentage composition; empirical and molecular formulae, each with the marking scheme of the real paper.
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Percentage composition; empirical and molecular formulae MCQs with solutions
10 of the 12 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.
The percentage by mass of an element in a compound is calculated as
- A. (mass of element in one mole of compound / molar mass of compound) × 100
- B. (molar mass of compound / mass of element in one mole) × 100
- C. mass of element × molar mass of compound
- D. moles of compound / moles of element
A compound contains carbon and oxygen in the mole ratio C:O = 1:2. What is its empirical formula?
- A. CO
- B. CO2
- C. C2O
- D. C2O4
The empirical formula of a compound is . Which information is additionally required to determine its molecular formula?
- A. Its colour
- B. Its molar mass
- C. Its melting point only
- D. Its physical state
A compound has empirical formula and molar mass . What is its molecular formula?
- A. NO2
- B. N2O4
- C. N3O6
- D. N4O8
What is the mass percentage of oxygen in water, ? Use H = 1 and O = 16.
- A. 11.1%
- B. 16.0%
- C. 88.9%
- D. 94.1%
A compound contains 40.0% carbon, 6.67% hydrogen and 53.33% oxygen by mass. What is its empirical formula? Use C = 12, H = 1 and O = 16.
- A. CHO
- B. CH2O
- C. C2H4O2
- D. CH4O
A compound has empirical formula and molar mass . What is its molecular formula?
- A. CH2
- B. C2H4
- C. C3H6
- D. C4H8
What is the mass percentage of nitrogen in ? Use N = 14, H = 1 and O = 16.
- A. 17.5%
- B. 28.0%
- C. 35.0%
- D. 70.0%
An oxide contains 69.9% iron and 30.1% oxygen by mass. Which empirical formula is closest? Use Fe = 55.85 and O = 16.
- A. FeO
- B. Fe2O3
- C. Fe3O4
- D. FeO2
A hydrocarbon contains 85.7% carbon and 14.3% hydrogen by mass. Its molar mass is . What is its molecular formula? Use C = 12 and H = 1.
- A. CH2
- B. C2H4
- C. C3H6
- D. C4H8
Common mistakes in Percentage composition; empirical and molecular formulae
Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.
- Uses the oxygen present in CO2 and H2O as if it all came from the sample, ignoring oxygen supplied during combustion.
- Correctly finds CH2O but forgets the final molar-mass step and reports the empirical formula as the molecular formula.
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