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NEET-UG and JEE Main Chemistry · Class 11

Concentration terms - molarity, molality and mole fraction — NEET & JEE Questions

Concentration terms - molarity, molality and mole fraction is a topic in Some Basic Concepts in Chemistry, a Class 11 Chemistry chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 70 published NEET-UG and JEE Main questions on Concentration terms - molarity, molality and mole fraction, each with the marking scheme of the real paper.

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Concentration terms - molarity, molality and mole fraction MCQs with solutions

10 of the 70 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    Molarity is defined as moles of solute per

    • A. litre of solution
    • B. kilogram of solvent
    • C. mole of solvent
    • D. litre of solvent only
  2. Question 2 · difficulty L2 · understanding

    20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _______ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol -1 )

  3. Question 3 · difficulty L2 · understanding

    Fortification of food with iron is done using FeSO4⋅7H2O\mathrm{FeSO}_4 \cdot 7 \mathrm{H}_2 \mathrm{O}. The mass in grams of the FeSO4\mathrm{FeSO}_4. 7H2O7 \mathrm{H}_2 \mathrm{O} required to achieve 12 ppm of iron in 150 kg of wheat is ______ (Nearest integer) [Given: Molar mass of Fe,S\mathrm{Fe}, \mathrm{S} and and O respectively are 56, 32 and 16 g mol−116 \mathrm{~g} \mathrm{~mol}^{-1} ]

  4. Question 4 · difficulty L2 · understanding

    The molarity of a 70%70 \% (mass/mass) aqueous solution of a monobasic acid (X) is _________ ×10−1\times 10^{-1} M (Nearest integer) [Given: Density of aqueous solution of (X) is 1.25 g mL−11.25 \mathrm{~g} \mathrm{~mL}^{-1} Molar mass of the acid is 70 g mol−170 \mathrm{~g} \mathrm{~mol}^{-1} ]

  5. Question 5 · difficulty L2 · understanding

    20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is _________ ×10−2M\times 10^{-2} \mathrm{M}. (Nearest integer)

  6. Question 6 · difficulty L2 · understanding

    A solution is prepared by adding 1 mole ethyl alcohol in 9 mole water. The mass percent of solute in the solution is ________ (Integer answer) (Given : Molar mass in g mol−1\mathrm{g} \mathrm{~mol}^{-1} Ethyl alcohol : 46 water : 18)

  7. Question 7 · difficulty L2 · understanding

    Molality of an aqueous solution of urea is 4.44 m4.44 \mathrm{~m}. Mole fraction of urea in solution is x×10−3x \times 10^{-3}, Value of xx is ________. (Integer answer)

  8. Question 8 · difficulty L2 · understanding

    The molarity of 1 L1 \mathrm{~L} orthophosphoric acid (H3PO4)\left(\mathrm{H}_3 \mathrm{PO}_4\right) having 70%70 \% purity by weight (specific gravity 1.54 g cm−31.54 \mathrm{~g} \mathrm{~cm}^{-3}) is __________ M\mathrm{M}. (Molar mass of H3PO4=98 g mol−1\mathrm{H}_3 \mathrm{PO}_4=98 \mathrm{~g} \mathrm{~mol}^{-1})

  9. Question 9 · difficulty L2 · understanding

    The mass of sodium acetate (CH3COONa)\left(\mathrm{CH}_3 \mathrm{COONa}\right) required to prepare 250 mL250 \mathrm{~mL} of 0.35 M0.35 \mathrm{~M} aqueous solution is ________ g. (Molar mass of CH3COONa\mathrm{CH}_3 \mathrm{COONa} is 82.02 g mol−182.02 \mathrm{~g} \mathrm{~mol}^{-1})

  10. Question 10 · difficulty L2 · understanding

    A solution of H2SO4\mathrm{H}_2 \mathrm{SO}_4 is 31.4%H2SO431.4 \% \mathrm{H}_2 \mathrm{SO}_4 by mass and has a density of 1.25 g/mL1.25 \mathrm{~g} / \mathrm{mL}. The molarity of the H2SO4\mathrm{H}_2 \mathrm{SO}_4 solution is _________ M\mathrm{M} (nearest integer) [Given molar mass of H2SO4=98 g mol−1\mathrm{H}_2 \mathrm{SO}_4=98 \mathrm{~g} \mathrm{~mol}^{-1}]

Common mistakes in Concentration terms - molarity, molality and mole fraction

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Uses total solution mass instead of solvent mass.
  • Assumes all concentration units depend on solution volume.
  • Uses 1080 g as the solvent mass, or ignores the density and assumes 1 L of solution is 1 kg of water.
  • Believes molality changes with temperature because 'the solution changes', or computes mole fraction as 1/55.56.

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