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NEET-UG and JEE Main Chemistry · Class 11

Specific, equivalent and molar conductivity; Kohlrausch's law — NEET & JEE Questions

Specific, equivalent and molar conductivity; Kohlrausch's law is a topic in Redox Reactions and Electrochemistry, a Class 11 Chemistry chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 12 published NEET-UG and JEE Main questions on Specific, equivalent and molar conductivity; Kohlrausch's law, each with the marking scheme of the real paper.

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Specific, equivalent and molar conductivity; Kohlrausch's law MCQs with solutions

10 of the 12 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    Molar conductivity is the conductance of the volume of solution containing

    • A. one mole of electrolyte
    • B. one gram of solvent
    • C. one litre of pure water
    • D. one equivalent of solvent
  2. Question 2 · difficulty L2 · understanding

    On dilution of an electrolyte solution, the specific conductivity generally

    • A. increases because ions move farther apart
    • B. decreases because the number of ions per unit volume decreases
    • C. remains exactly constant
    • D. becomes infinite
  3. Question 3 · difficulty L2 · understanding

    On dilution, molar conductivity of an electrolyte generally

    • A. decreases
    • B. increases
    • C. remains zero
    • D. becomes independent of ion mobility
  4. Question 4 · difficulty L2 · understanding

    Kohlrausch's law at infinite dilution states that the limiting molar conductivity of an electrolyte is

    • A. the sum of independent limiting ionic contributions of its ions
    • B. always zero
    • C. equal only to the cation contribution
    • D. independent of which ions are present
  5. Question 5 · difficulty L3 · application

    A solution has conductivity κ=1.0×10−3 S cm−1\kappa=1.0\times10^{-3}\,\text{S cm}^{-1} and concentration 0.010 mol L−10.010\,\text{mol L}^{-1}. What is its molar conductivity?

    • A. 10 S cm² mol⁻¹
    • B. 50 S cm² mol⁻¹
    • C. 100 S cm² mol⁻¹
    • D. 1000 S cm² mol⁻¹
  6. Question 6 · difficulty L3 · application

    At infinite dilution, λNa+∘=50.1\lambda^\circ_{Na^+}=50.1 and λCl−∘=76.3\lambda^\circ_{Cl^-}=76.3 S cm² mol⁻¹. What is Λm∘\Lambda_m^\circ for NaCl?

    • A. 26.2 S cm² mol⁻¹
    • B. 50.1 S cm² mol⁻¹
    • C. 76.3 S cm² mol⁻¹
    • D. 126.4 S cm² mol⁻¹
  7. Question 7 · difficulty L3 · application

    The molar conductivity of a weak electrolyte at a certain concentration is 40 S cm² mol⁻¹ and its limiting molar conductivity is 400 S cm² mol⁻¹. Estimate its degree of dissociation.

    • A. 0.01
    • B. 0.10
    • C. 0.40
    • D. 10
  8. Question 8 · difficulty L3 · application

    Which electrolyte is expected to show a much sharper increase in molar conductivity on dilution?

    • A. A weak electrolyte such as acetic acid
    • B. A strong electrolyte such as KCl
    • C. A non-electrolyte such as glucose
    • D. A metal wire
  9. Question 9 · difficulty L4 · application

    At infinite dilution, Λm∘(HCl)=426\Lambda_m^\circ(HCl)=426, Λm∘(NaCl)=126\Lambda_m^\circ(NaCl)=126 and Λm∘(NaA)=91\Lambda_m^\circ(NaA)=91 S cm² mol⁻¹. Using Kohlrausch's law, estimate Λm∘(HA)\Lambda_m^\circ(HA) for the weak acid HA.

    • A. 299 S cm² mol⁻¹
    • B. 391 S cm² mol⁻¹
    • C. 517 S cm² mol⁻¹
    • D. 643 S cm² mol⁻¹
  10. Question 10 · difficulty L4 · application

    A 0.020 M solution has conductivity 2.5×10−3 S cm−12.5\times10^{-3}\,\text{S cm}^{-1}. What is its molar conductivity?

    • A. 12.5 S cm² mol⁻¹
    • B. 50 S cm² mol⁻¹
    • C. 125 S cm² mol⁻¹
    • D. 500 S cm² mol⁻¹

Common mistakes in Specific, equivalent and molar conductivity; Kohlrausch's law

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Stops after finding $\alpha=0.10$ and reports it as a molar concentration.
  • Uses molar conductivity directly in the equilibrium expression instead of first converting it to degree of ionisation.

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