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NEET-UG and JEE Main Chemistry · Class 11

Electrochemical cells, EMF and the electrochemical series — NEET & JEE Questions

Electrochemical cells, EMF and the electrochemical series is a topic in Redox Reactions and Electrochemistry, a Class 11 Chemistry chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 95 published NEET-UG and JEE Main questions on Electrochemical cells, EMF and the electrochemical series, each with the marking scheme of the real paper.

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Electrochemical cells, EMF and the electrochemical series MCQs with solutions

10 of the 95 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    In a galvanic cell, oxidation occurs at the

    • A. anode
    • B. cathode
    • C. salt bridge
    • D. voltmeter
  2. Question 2 · difficulty L2 · understanding

    The hydrogen electrode is dipped in a solution of pH=3\mathrm{pH}=3 at 25∘C25^{\circ} \mathrm{C}. The potential of the electrode will be _________ ×10−2 V\times 10^{-2} \mathrm{~V}. (2.303RTF=0.059 V)\left(\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{~V}\right)

  3. Question 3 · difficulty L2 · understanding

    In a cell, the following reactions take place \begin{aligned}\matrix{ {F{e^{2 + }} \to F{e^{3 + }} + {e^ - }} & {E_{F{e^{3 + }}/F{e^{2 + }}}^o = 0.77\,V} \cr {2{I^ - } \to {I_2} + 2{e^ - }} & {E_{{I_2}/{I^ - }}^o = 0.54\,V} \cr } \end{aligned} The standard electrode potential for the spontaneous reaction in the cell is x ×\times 10 −-2 V 298 K. The value of x is ____________. (Nearest Integer)

  4. Question 4 · difficulty L2 · understanding

    Given at 298 K : EFe2+/Fe⊖=X Volt EFe3+/Fe⊖=Y Volt  \begin{aligned} & \mathrm{E}_{\mathrm{Fe}^{2+} / \mathrm{Fe}}^{\ominus}=\mathrm{X} \text { Volt } \\ & \mathrm{E}_{\mathrm{Fe}^{3+} / \mathrm{Fe}}^{\ominus}=\mathrm{Y} \text { Volt } \end{aligned} The EFe3+/Fe2+⊖\mathrm{E}_{\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}}^{\ominus} in Volt at 298 K is given by :

    • A. 2X−3Y2 \mathrm{X}-3 \mathrm{Y}
    • B. 3Y−2X3 Y-2 X
    • C. 3Y+2X3 \mathrm{Y}+2 \mathrm{X}
    • D. Y+XY+X
  5. Question 5 · difficulty L2 · understanding

    Consider the following reduction processes : Al3++3e−⟶Al( s),E0=−1.66 VFe3++e−⟶Fe2+,E0=+0.77 VCo3++e−⟶Co2+,E0=+1.81 VCr3++3e−⟶Cr( s),E0=−0.74 V \begin{aligned} & \mathrm{Al}^{3+}+3 \mathrm{e}^{-} \longrightarrow \mathrm{Al}(\mathrm{~s}), \mathrm{E}^0=-1.66 \mathrm{~V} \\ & \mathrm{Fe}^{3+}+\mathrm{e}^{-} \longrightarrow \mathrm{Fe}^{2+}, \mathrm{E}^0=+0.77 \mathrm{~V} \\ & \mathrm{Co}^{3+}+\mathrm{e}^{-} \longrightarrow \mathrm{Co}^{2+}, \mathrm{E}^0=+1.81 \mathrm{~V} \\ & \mathrm{Cr}^{3+}+3 \mathrm{e}^{-} \longrightarrow \mathrm{Cr}(\mathrm{~s}), \mathrm{E}^0=-0.74 \mathrm{~V} \end{aligned} The tendency to act as reducing agent decreases in the order :

    • A. Al>Fe2+>Cr>Co2+\mathrm{Al}>\mathrm{Fe}^{2+}>\mathrm{Cr}>\mathrm{Co}^{2+}
    • B. Al>Cr>Co2+>Fe2+\mathrm{Al}>\mathrm{Cr}>\mathrm{Co}^{2+}>\mathrm{Fe}^{2+}
    • C. Cr>Fe2+>Al>Co2+\mathrm{Cr}>\mathrm{Fe}^{2+}>\mathrm{Al}>\mathrm{Co}^{2+}
    • D. Al>Cr>Fe2+>Co2+\mathrm{Al}>\mathrm{Cr}>\mathrm{Fe}^{2+}>\mathrm{Co}^{2+}
  6. Question 6 · difficulty L2 · understanding

    The standard reduction potential values of some of the p-block ions are given below. Predict the one with the strongest oxidising capacity.

    • A. ESn4+/Sn2+o=+1.15 VE^o_{\text{Sn}^{4+}/\text{Sn}^{2+}} = +1.15 \text{ V}
    • B. EAl3+/Alo=−1.66 VE^o_{\text{Al}^{3+}/\text{Al}} = -1.66 \text{ V}
    • C. EPb4+/Pb2+o=+1.67 VE^o_{\text{Pb}^{4+}/\text{Pb}^{2+}} = +1.67 \text{ V}
    • D. ETl3+/Tlo=+1.26 VE^o_{\text{Tl}^{3+}/\text{Tl}} = +1.26 \text{ V}
  7. Question 7 · difficulty L2 · understanding

    Based on the data given below : ECr2O72−/Cr3+∘=1.33 VECl2/Cl(−)∘=1.36 VEMnO4−/Mn2+0=1.51 VECr3+/Cr∘=−0.74 V\begin{array}{ll} \mathrm{E}_{\mathrm{Cr}_2 \mathrm{O}_7^{2-} / \mathrm{Cr}^{3+}}^{\circ}=1.33 \mathrm{~V} & \mathrm{E}_{\mathrm{Cl}_2 / \mathrm{Cl}^{(-)}}^{\circ}=1.36 \mathrm{~V} \\ \mathrm{E}_{\mathrm{MnO}_4^{-} / \mathrm{Mn}^{2+}}^0=1.51 \mathrm{~V} & \mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^{\circ}=-0.74 \mathrm{~V} \end{array} the strongest reducing agent is :

    • A. Cl−\mathrm{Cl}^{-}
    • B. MnO4−\mathrm{MnO}_4^{-}
    • C. Cr\mathrm{Cr}
    • D. Mn2+\mathrm{Mn}^{2+}
  8. Question 8 · difficulty L2 · understanding

    One of the commonly used electrode is calomel electrode. Under which of the following categories, calomel electrode comes?

    • A. Metal ion - Metal electrodes
    • B. Oxidation - Reduction electrodes
    • C. Metal - Insoluble Salt - Anion electrodes
    • D. Gas - Ion electrodes
  9. Question 9 · difficulty L2 · understanding

    Reduction potential of ions are given below: ClO4−IO4−BrO4−E∘=1.19 VE∘=1.65 VE∘=1.74 V\begin{array}{ccc} \mathrm{ClO}_4^{-} & \mathrm{IO}_4^{-} & \mathrm{BrO}_4^{-} \\ \mathrm{E}^{\circ}=1.19 \mathrm{~V} & \mathrm{E}^{\circ}=1.65 \mathrm{~V} & \mathrm{E}^{\circ}=1.74 \mathrm{~V} \end{array} The correct order of their oxidising power is :

    • A. IO4−>BrO4−>ClO4−\mathrm{IO}_4^{-}>\mathrm{BrO}_4^{-}>\mathrm{ClO}_4^{-}
    • B. BrO4−>ClO4−>IO4−\mathrm{BrO}_4^{-}>\mathrm{ClO}_4^{-}>\mathrm{IO}_4^{-}
    • C. ClO4−>IO4−>BrO4−\mathrm{ClO}_4^{-}>\mathrm{IO}_4^{-}>\mathrm{BrO}_4^{-}
    • D. BrO4−>IO4−>ClO4−\mathrm{BrO}_4^{-}>\mathrm{IO}_4^{-}>\mathrm{ClO}_4^{-}
  10. Question 10 · difficulty L2 · understanding

    In 3d series, the metal having the highest M 2+ /M standard electrode potential is :

    • A. Cr
    • B. Fe
    • C. Cu
    • D. Zn

Common mistakes in Electrochemical cells, EMF and the electrochemical series

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Adds the listed reduction potentials without reversing the anode contribution.

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