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NEET-UG and JEE Main Physics · Class 11

Relative velocity — NEET & JEE Questions

Relative velocity is a topic in Kinematics, a Class 11 Physics chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 26 published NEET-UG and JEE Main questions on Relative velocity, each with the marking scheme of the real paper.

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Relative velocity MCQs with solutions

10 of the 26 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    The velocity of A relative to B is

    • A. v⃗AB=v⃗A−v⃗B\vec v_{AB}=\vec v_A-\vec v_B
    • B. v⃗A+v⃗B\vec v_A+\vec v_B
    • C. v⃗B−v⃗A\vec v_B-\vec v_A only
    • D. v⃗Av⃗B\vec v_A\vec v_B
  2. Question 2 · difficulty L2 · understanding

    Train A is moving along two parallel rail tracks towards north with speed 72 km/h72 \mathrm{~km} / \mathrm{h} and train B is moving towards south with speed 108 km/h108 \mathrm{~km} / \mathrm{h}. Velocity of train B with respect to A and velocity of ground with respect to B are (in ms−1\mathrm{ms}^{-1}):

    • A. -50 and -30
    • B. -50 and 30
    • C. -30 and 50
    • D. 50 and -30
  3. Question 3 · difficulty L2 · understanding

    A passenger sitting in a train A moving at 90 km/h90 \mathrm{~km} / \mathrm{h} observes another train B\mathrm{B} moving in the opposite direction for 8 s8 \mathrm{~s}. If the velocity of the train B is 54 km/h54 \mathrm{~km} / \mathrm{h}, then length of train B is:

    • A. 80 m
    • B. 200 m
    • C. 120 m
    • D. 320 m
  4. Question 4 · difficulty L2 · understanding

    Two buses P and Q start from a point at the same time and move in a straight line and their positions are represented by XP(t)=αt+βt2{X_P}(t) = \alpha t + \beta {t^2} and XQ(t)=ft−t2{X_Q}(t) = ft - {t^2}. At what time, both the buses have same velocity?

    • A. α−f1+β{{\alpha - f} \over {1 + \beta }}
    • B. α+f2(β−1){{\alpha + f} \over {2(\beta - 1)}}
    • C. α+f2(1+β){{\alpha + f} \over {2(1 + \beta )}}
    • D. f−α2(1+β){{f - \alpha } \over {2(1 + \beta )}}
  5. Question 5 · difficulty L2 · understanding

    A boy reaches the airport and finds that the escalator is not working. He walks up the stationary escalator in time t 1 . If he remains stationary on a moving escalator then the escalator takes him up in time t 2 . The time taken by him to walk up on the moving escalator will be :

    • A. t1t2t2−t1{{{t_1}{t_2}} \over {{t_2} - {t_1}}}
    • B. t1+t22{{{t_1} + {t_2}} \over 2}
    • C. t1t2t2+t1{{{t_1}{t_2}} \over {{t_2} + {t_1}}}
    • D. t2−t1{t_2} - {t_1}
  6. Question 6 · difficulty L2 · understanding

    The position vector of a moving body at any instant of time is given as r→=(5t2i^−5tj^)m\overrightarrow{\mathrm{r}}=\left(5 \mathrm{t}^2 \hat{i}-5 \mathrm{t} \hat{j}\right) \mathrm{m}. The magnitude and direction of velocity at t=2st=2 s is,

    • A. 517 m/s5 \sqrt{17} \mathrm{~m} / \mathrm{s}, making an angle of tan⁡−14\tan ^{-1} 4 with - ve Y axis
    • B. 515 m/s5 \sqrt{15} \mathrm{~m} / \mathrm{s}, making an angle of tan⁡−14\tan ^{-1} 4 with + ve XX axis
    • C. 517 m/s5 \sqrt{17} \mathrm{~m} / \mathrm{s}, making an angle of tan⁡−14\tan ^{-1} 4 with + ve XX axis
    • D. 515 m/s5 \sqrt{15} \mathrm{~m} / \mathrm{s}, making an angle of tan⁡−14\tan ^{-1} 4 with −- ve YY axis
  7. Question 7 · difficulty L2 · understanding

    Position of an ant (S\mathrm{S} in metres) moving in Y\mathrm{Y}-Z\mathrm{Z} plane is given by S=2t2j^+5k^S=2 t^2 \hat{j}+5 \hat{k} (where tt is in second). The magnitude and direction of velocity of the ant at t=1 s\mathrm{t}=1 \mathrm{~s} will be :

    • A. 16 m/s16 \mathrm{~m} / \mathrm{s} in yy-direction
    • B. 4 m/s4 \mathrm{~m} / \mathrm{s} in xx-direction
    • C. 9 m/s9 \mathrm{~m} / \mathrm{s} in z\mathrm{z}-direction
    • D. 4 m/s4 \mathrm{~m} / \mathrm{s} in yy-direction
  8. Question 8 · difficulty L2 · understanding

    At time t=0t=0 a particle starts travelling from a height 7z^ cm7 \hat{z} \mathrm{~cm} in a plane keeping z coordinate constant. At any instant of time it's position along the x^\hat{x} and y^\hat{y} directions are defined as 3t3 \mathrm{t} and 5t35 \mathrm{t}^{3} respectively. At t = 1s acceleration of the particle will be

    • A. −30y^-30 \hat{y}
    • B. 30y^30 \hat{y}
    • C. 3x^+15y^3 \hat{x}+15 \hat{y}
    • D. 3x^+15y^+7z^3 \hat{x}+15 \hat{y}+7 \hat{z}
  9. Question 9 · difficulty L2 · understanding

    The speed of a swimmer is 4 km h−14 \mathrm{~km} \mathrm{~h}^{-1} in still water. If the swimmer makes his strokes normal to the flow of river of width 1 km1 \mathrm{~km}, he reaches a point 750 m750 \mathrm{~m} down the stream on the opposite bank. The speed of the river water is ___________ km h−1\mathrm{km} ~\mathrm{h}^{-1}

  10. Question 10 · difficulty L2 · understanding

    A swimmer wants to cross a river from point A to point B. Line AB makes an angle of 30∘^\circ with the flow of river. Magnitude of velocity of the swimmer is same as that of the river. The angle θ\theta with the line AB should be _________∘^\circ, so that the swimmer reaches point B.

Common mistakes in Relative velocity

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Adds same-direction velocities instead of subtracting.
  • Subtracts speeds even when the objects move in opposite directions.

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