Skip to content

NEET-UG and JEE Main Physics · Class 11

Motion in a plane; projectile motion — NEET & JEE Questions

Motion in a plane; projectile motion is a topic in Kinematics, a Class 11 Physics chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 62 published NEET-UG and JEE Main questions on Motion in a plane; projectile motion, each with the marking scheme of the real paper.

questions
62
shown here
10
Test me on this topic

Five free tests with an account. Your score comes with the result; where you stand is Pro.

Motion in a plane; projectile motion MCQs with solutions

10 of the 62 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    In ideal projectile motion without air resistance, the horizontal acceleration is

    • A. zero
    • B. g downward
    • C. g upward
    • D. dependent on projectile mass
  2. Question 2 · difficulty L2 · understanding

    A gun mounted on the ground fires bullets in all directions with same speed. The farthest distance the bullets could reach is 6.4 m . The speed of the bullets from the gun is ____\_\_\_\_ m/s\mathrm{m} / \mathrm{s}.  (take g=10 m/s2 )  \text { (take } \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2 \text { ) }

  3. Question 3 · difficulty L2 · understanding

    The maximum height reached by a projectile is 64 m64 \mathrm{~m}. If the initial velocity is halved, the new maximum height of the projectile is ______ m\mathrm{m}.

  4. Question 4 · difficulty L2 · understanding

    Two bodies are projected from ground with same speeds 40 ms−140 \mathrm{~ms}^{-1} at two different angles with respect to horizontal. The bodies were found to have same range. If one of the body was projected at an angle of 60∘60^{\circ}, with horizontal then sum of the maximum heights, attained by the two projectiles, is m\mathrm{m}. (Given g=10 ms−2\mathrm{g}=10 \mathrm{~ms}^{-2} )

  5. Question 5 · difficulty L2 · understanding

    A fighter jet is flying horizontally at a certain altitude with a speed of 200 ms −-1 . When it passes directly overhead an anti-aircraft gun, a bullet is fired from the gun, at an angle θ\theta with the horizontal, to hit the jet. If the bullet speed is 400 m/s, the value of θ\theta will be ___________∘^\circ.

  6. Question 6 · difficulty L2 · understanding

    At t=0t=0, a body of mass 100 g starts moving under the influence of a force (5i^+10j^)N⋅(5 \hat{\mathrm{i}}+10 \hat{\mathrm{j}}) \mathrm{N} \cdot After 2 s its position is (2xi^+5yj^)m(2 x \hat{\mathrm{i}}+5 y \hat{\mathrm{j}}) \mathrm{m}. The ratio x:yx: y is ____\_\_\_\_ .

    • A. 1:21: 2
    • B. 2:52: 5
    • C. 5:25 : 2
    • D. 5:45: 4
  7. Question 7 · difficulty L2 · understanding

    If xx and yy coordinates of a projectile as a function of time (t)(t) are given as 24t24 t and 43.6t−4.9t243.6 t-4.9 t^2, respectively, then the angle (in degrees) made by the projectile with horizontal when t=2 st=2 \mathrm{~s} is ____\_\_\_\_ .

    • A. 60
    • B. 45
    • C. 30
    • D. 75
  8. Question 8 · difficulty L2 · understanding

    The two projectiles are projected with the same initial velocities at the 15∘15^{\circ} and 30∘30^{\circ} with respect to the horizontal. The ratio of their ranges is 1:x1: x. The value of xx is

    • A. 2\sqrt{2}
    • B. 3 \sqrt{3}
    • C. 232 \sqrt{3}
    • D. 12 \frac{1}{\sqrt{2}}
  9. Question 9 · difficulty L2 · understanding

    A helicopter flying horizontally with a speed of 360 km/h at an altitude of 2 km, drops an object at an instant. The object hits the ground at a point O, 20 s after it is dropped. Displacement of 'O' from the position of helicopter where the object was released is : (use acceleration due to gravity g = 10 m/s 2 and neglect air resistance)

    • A. 7.2 km
    • B. 25\sqrt{5} km
    • C. 22\sqrt{2} km
    • D. 4 km
  10. Question 10 · difficulty L2 · understanding

    Two projectiles are fired from ground with same initial speeds from same point at angles (45∘+\left(45^{\circ}+\right. α)\alpha) and (45∘−α)\left(45^{\circ}-\alpha\right) with horizontal direction. The ratio of their times of flights is

    • A. 1+tan⁡α1−tan⁡α\frac{1+\tan \alpha}{1-\tan \alpha}
    • B. 1+sin⁡2α1−sin⁡2α\frac{1+\sin 2 \alpha}{1-\sin 2 \alpha}
    • C. 1−tan⁡α1+tan⁡α\frac{1-\tan \alpha}{1+\tan \alpha}
    • D. 1

Common mistakes in Motion in a plane; projectile motion

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Uses vertical acceleration in the horizontal displacement calculation.
  • Interchanges sine and cosine components.
  • Assumes equal range requires equal vertical components or flight times.

Practise this chapter

Reading a question and answering it under a clock are different things. A chapter-length test measures whether the topic went in.