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NEET-UG and JEE Main Physics · Class 11

Degrees of freedom, equipartition and specific heats — NEET & JEE Questions

Degrees of freedom, equipartition and specific heats is a topic in Kinetic Theory of Gases, a Class 11 Physics chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 47 published NEET-UG and JEE Main questions on Degrees of freedom, equipartition and specific heats, each with the marking scheme of the real paper.

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Degrees of freedom, equipartition and specific heats MCQs with solutions

10 of the 47 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    According to equipartition, each independent quadratic degree of freedom contributes an average energy of

    • A. 12kBT\frac12 k_BT
    • B. kBTk_BT
    • C. 2kBT2k_BT
    • D. 14kBT\frac14 k_BT
  2. Question 2 · difficulty L2 · understanding

    The internal energy of air in 4 m×4 m×3 m4 \mathrm{~m} \times 4 \mathrm{~m} \times 3 \mathrm{~m} sized room at 1 atmospheric pressure will be___________________×106 J\times 10^6 \mathrm{~J} (Consider air as diatomic molecule)

  3. Question 3 · difficulty L2 · understanding

    The total internal energy of two mole monoatomic ideal gas at temperature T = 300 K will be _____________ J. (Given R = 8.31 J/mol.K)

  4. Question 4 · difficulty L2 · understanding

    If 2 mole of an ideal monoatomic gas at temperature TT, is mixed with 6 mole of another ideal monoatomic gas at temperature 2T2 T then the temperature of mixture is:

    • A. 52T\frac{5}{2} T
    • B. 54T\frac{5}{4} T
    • C. 72T\frac{7}{2} T
    • D. 74T\frac{7}{4} T
  5. Question 5 · difficulty L2 · understanding

    Match the List I with List II List - I List - II (A) Triatomic rigid gas (I) CpCv=53\frac{C_p}{C_v}=\frac{5}{3} (B) Diatomic non-rigid gas (II) CpCv=75\frac{C_p}{C_v}=\frac{7}{5} (C) Monoatomic gas (III) CpCv=43\frac{C_p}{C_v}=\frac{4}{3} (D) Diatomic rigid gas (IV) CpCv=97\frac{C_p}{C_v}=\frac{9}{7} Choose the correct answer from the options given below:

    • A. A-III, B-IV, C-I, D-II
    • B. A-II, B-IV, C-I, D-III
    • C. A-IV, B-II, C-III, D-I
    • D. A-III, B-II, C-IV, D-I
  6. Question 6 · difficulty L2 · understanding

    A mixture of one mole of monoatomic gas and one mole of a diatomic gas (rigid) are kept at room temperature (27∘C)(27^{\circ} \mathrm{C}). The ratio of specific heat of gases at constant volume respectively is:

    • A. 32\frac{3}{2}
    • B. 35\frac{3}{5}
    • C. 75\frac{7}{5}
    • D. 53\frac{5}{3}
  7. Question 7 · difficulty L2 · understanding

    The translational degrees of freedom (ft)\left(f_t\right) and rotational degrees of freedom (fr)\left(f_r\right) of CH4\mathrm{CH}_4 molecule are:

    • A. ft=2f_t=2 and fr=2f_r=2
    • B. ft=3f_t=3 and fr=3f_r=3
    • C. ft=3f_t=3 and 4fr=2f_r=2$
    • D. ft=2f_t=2 and fr=3f_r=3
  8. Question 8 · difficulty L2 · understanding

    Two moles a monoatomic gas is mixed with six moles of a diatomic gas. The molar specific heat of the mixture at constant volume is :

    • A. 32R\frac{3}{2} \mathrm{R}
    • B. 74R\frac{7}{4} \mathrm{R}
    • C. 52R\frac{5}{2} \mathrm{R}
    • D. 94R\frac{9}{4} \mathrm{R}
  9. Question 9 · difficulty L2 · understanding

    The mean free path of molecules of a certain gas at STP is 1500 d1500 \mathrm{~d}, where d\mathrm{d} is the diameter of the gas molecules. While maintaining the standard pressure, the mean free path of the molecules at 373 K373 \mathrm{~K} is approximately:

    • A. 750 d750 \mathrm{~d}
    • B. 1500 d1500 \mathrm{~d}
    • C. 2049 d\mathrm{2049~ d}
    • D. 1098 d1098 \mathrm{~d}
  10. Question 10 · difficulty L2 · understanding

    Three vessels of equal volume contain gases at the same temperature and pressure. The first vessel contains neon (monoatomic), the second contains chlorine (diatomic) and third contains uranium hexafloride (polyatomic). Arrange these on the basis of their root mean square speed (vrms)\left(v_{\mathrm{rms}}\right) and choose the correct answer from the options given below:

    • A. vrms(\mathrm{v}_{\mathrm{rms}}( mono )=vrms()=\mathrm{v}_{\mathrm{rms}}( dia )=vrms()=\mathrm{v}_{\mathrm{rms}}( poly ))
    • B. vrms\mathrm{v}_{\mathrm{rms}} (mono) >vrms( > \mathrm{v}_{\mathrm{rms}}( dia )>vrms) > \mathrm{v}_{\mathrm{rms}} (poly)
    • C. vrms\mathrm{v}_{\mathrm{rms}} (dia) <vrms < \mathrm{v}_{\mathrm{rms}} (poly) <vrms  < \mathrm{v}_{\text {rms }} (mono)
    • D. vrms\mathrm{v}_{\mathrm{rms}} (mono) <vrms < \mathrm{v}_{\mathrm{rms}} (dia) <vrms < \mathrm{v}_{\mathrm{rms}} (poly)

Common mistakes in Degrees of freedom, equipartition and specific heats

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Uses a polyatomic specific-heat expression for a monatomic gas.
  • Adds an extra R as though calculating $C_P$.
  • Assumes equal temperature implies equal internal energy for gases with different degrees of freedom.

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