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NEET-UG and JEE Main Physics · Class 11

Mean free path and Avogadro's number — NEET & JEE Questions

Mean free path and Avogadro's number is a topic in Kinetic Theory of Gases, a Class 11 Physics chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 12 published NEET-UG and JEE Main questions on Mean free path and Avogadro's number, each with the marking scheme of the real paper.

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Mean free path and Avogadro's number MCQs with solutions

10 of the 12 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    Mean free path is the average distance travelled by a gas molecule between

    • A. successive collisions
    • B. successive wall reflections only
    • C. two phase changes
    • D. two chemical reactions
  2. Question 2 · difficulty L2 · understanding

    At fixed temperature, decreasing gas pressure generally causes the mean free path to

    • A. increase
    • B. decrease
    • C. remain exactly constant
    • D. become zero
  3. Question 3 · difficulty L2 · understanding

    Avogadro's number represents the number of constituent particles in

    • A. one mole
    • B. one kilogram
    • C. one litre of every substance
    • D. one atom
  4. Question 4 · difficulty L2 · understanding

    The numerical value of Avogadro's constant is approximately

    • A. 6.02×1023 mol−16.02\times10^{23}\,mol^{-1}
    • B. 6.02×10−23 mol−16.02\times10^{-23}\,mol^{-1}
    • C. 3.00×108 mol−13.00\times10^8\,mol^{-1}
    • D. 1.38×10−23 mol−11.38\times10^{-23}\,mol^{-1}
  5. Question 5 · difficulty L3 · application

    How many molecules are present in 2 mol of an ideal gas?

    • A. 1.204×10241.204\times10^{24}
    • B. 6.02×10236.02\times10^{23}
    • C. 3.01×10233.01\times10^{23}
    • D. 2.00×10232.00\times10^{23}
  6. Question 6 · difficulty L3 · application

    A sample contains 3.01×10233.01\times10^{23} molecules. How many moles is this approximately?

    • A. 0.50 mol
    • B. 1.0 mol
    • C. 2.0 mol
    • D. 3.01 mol
  7. Question 7 · difficulty L3 · application

    At constant temperature, if gas pressure is reduced to one-half and molecular diameter is unchanged, mean free path approximately becomes

    • A. twice
    • B. half
    • C. four times
    • D. unchanged
  8. Question 8 · difficulty L3 · application

    Which change would most directly increase mean free path in a gas at fixed pressure?

    • A. Increasing temperature
    • B. Increasing molecular diameter
    • C. Increasing number density
    • D. Compressing the gas
  9. Question 9 · difficulty L4 · application

    A gas has mean free path λ\lambda at pressure P. At the same temperature its pressure becomes 4P. What is the new mean free path?

    • A. λ/4\lambda/4
    • B. 4λ4\lambda
    • C. λ/2\lambda/2
    • D. 2λ2\lambda
  10. Question 10 · difficulty L4 · application

    A 0.25 mol gas sample contains how many molecules approximately?

    • A. 1.51×10231.51\times10^{23}
    • B. 2.41×10242.41\times10^{24}
    • C. 6.02×10236.02\times10^{23}
    • D. 4.00×10224.00\times10^{22}

Common mistakes in Mean free path and Avogadro's number

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Changes a universal constant rather than the gas number density.
  • Focuses on faster molecular motion and predicts shorter distance between collisions.

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