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NEET-UG and JEE Main Chemistry · Class 12

Solubility of gases and solids; Henry's law — NEET & JEE Questions

Solubility of gases and solids; Henry's law is a topic in Solutions, a Class 12 Chemistry chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 16 published NEET-UG and JEE Main questions on Solubility of gases and solids; Henry's law, each with the marking scheme of the real paper.

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Solubility of gases and solids; Henry's law MCQs with solutions

10 of the 16 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    According to Henry's law, at a constant temperature the partial pressure of a gas in the vapour phase is directly proportional to

    • A. the volume of the solvent
    • B. the mole fraction of the gas in the solution
    • C. the temperature of the solution
    • D. the molar mass of the gas
  2. Question 2 · difficulty L2 · understanding

    If O2\mathrm{O}_{2} gas is bubbled through water at 303 K303 \mathrm{~K}, the number of millimoles of O2\mathrm{O}_{2} gas that dissolve in 1 litre of water is __________. (Nearest Integer) (Given : Henry's Law constant for O2\mathrm{O}_{2} at 303 K303 \mathrm{~K} is 46.82 k46.82 \,\mathrm{k} bar and partial pressure of O2=0.920\mathrm{O}_{2}=0.920 bar) (Assume solubility of O2\mathrm{O}_{2} in water is too small, nearly negligible)

  3. Question 3 · difficulty L2 · understanding

    A company dissolves 'x' amount of CO 2 at 298 K in 1 litre of water to prepare soda water. X = __________ ×\times 10 −-3 g. (nearest integer) (Given : partial pressure of CO 2 at 298 K = 0.835 bar. Henry's law constant for CO 2 at 298 K = 1.67 kbar. Atomic mass of H, C and O is 1, 12, and 6 g mol −-1 , respectively)

  4. Question 4 · difficulty L2 · understanding

    CO 2 gas is bubbled through water during a soft drink manufacturing process at 298 K. If CO 2 exerts a partial pressure of 0.835 bar then x m mol of CO 2 would dissolve in 0.9 L of water. The value of x is ____________. (Nearest integer) (Henry's law constant for CO 2 at 298 K is 1.67 ×\times 10 3 bar)

  5. Question 5 · difficulty L2 · understanding

    The oxygen dissolved in water exerts a partial pressure of 20 kPa in the vapour above water. The molar solubility of oxygen in water is __________ ×\times 10 −-5 mol dm −-3 . (Round off to the Nearest Integer). [Given : Henry's law constant = K H = 8.0 ×\times 10 4 kPa for O 2 . Density of water with dissolved oxygen = 1.0 kg dm −-3 ]

  6. Question 6 · difficulty L3 · understanding

    At 298 K , the mole percentage of N2( g)\mathrm{N}_2(\mathrm{~g}) in air is 80%80 \%. Water is in equilibrium with air at a pressure of 10 atm . What is the mole fraction of N2( g)\mathrm{N}_2(\mathrm{~g}) in water at 298 K ? (KH\left(\mathrm{K}_{\mathrm{H}}\right. for N2\mathrm{N}_2 is 6.5×107 mmHg)\left.6.5 \times 10^7 \mathrm{~mm} \mathrm{Hg}\right)

    • A. 9.35×10−59.35 \times 10^{-5}
    • B. 9.35×1059.35 \times 10^5
    • C. 1.23×10−71.23 \times 10^{-7}
    • D. 1.17×10−41.17 \times 10^{-4}
  7. Question 7 · difficulty L3 · understanding

    Given below are two statements : Statement I : The Henry's law constant KH\mathrm{K}_{\mathrm{H}} is constant with respect to variations in solution's concentration over the range for which the solution is ideally dilute. Statement II : KH\mathrm{K}_{\mathrm{H}} does not differ for the same solute in different solvents. In the light of the above statements, choose the correct answer from the options given below

    • A. Both Statement I and Statement II are true
    • B. Statement I is true but Statement II is false
    • C. Statement I is false but Statement II is true
    • D. Both Statement I and Statement II are false
  8. Question 8 · difficulty L3 · understanding

    For a solution of the gases A, B, C and D in water at 298 K, the values of Henry's law constant (K H ) are 30.40, 2.34, 1.56 ×\times 10 −-5 and 0.513 k bar respectively. In the given graph, the lines marked as 'p' and 's' correspond respectively to :

    • A. A and C
    • B. B and A
    • C. D and A
    • D. C and D
  9. Question 9 · difficulty L3 · understanding

    Sea water, which can be considered as a 6 molar (6M)(6 \mathrm{M}) solution of NaCl , has a density of 2 g mL−12 \mathrm{~g} \mathrm{~mL}^{-1}. The concentration of dissolved oxygen (O2)\left(\mathrm{O}_2\right) in sea water is 5.8 ppm . Then the concentration of dissolved oxygen (O2)\left(\mathrm{O}_2\right) in sea water, is x×10−4 mx \times 10^{-4} \mathrm{~m}. x=x= ___________. (Nearest integer) Given: Molar mass of NaCl is 58.5 g mol−158.5 \mathrm{~g} \mathrm{~mol}^{-1} Molar mass of O2\mathrm{O}_2 is 32 g mol−132 \mathrm{~g} \mathrm{~mol}^{-1}

  10. Question 10 · difficulty L3 · understanding

    Identify the correct statements : (A) The molality of 2.5 g of ethanoic acid (Molar mass : 60 g mol−160 \mathrm{~g} \mathrm{~mol}^{-1} ) in 75 g of benzene solution is 0.556 m . (B) The molarity of a solution containing 5 g of NaOH (molar mass : 40 g mol−140 \mathrm{~g} \mathrm{~mol}^{-1} ) in 450 mL of solution is 0.278 M at 298 K . (C) Aquatic species are more comfortable in cold water. (D) The solubility of gas increases with decrease in pressure. (E) For a binary mixture of AA and BB, the number of moles of AA and BB are nAn_A and nBn_B respectively. The mole fraction of BB will be xB=nAnA+nBx_B=\frac{n_A}{n_A+n_B}. Choose the correct answer from the options given below :

    • A. A, B and C only
    • B. A and B only
    • C. A and C only
    • D. A, D and E only

Common mistakes in Solubility of gases and solids; Henry's law

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Reads a large $K_H$ as high solubility.
  • Assumes the diluent must be more soluble to 'hold' the nitrogen in.
  • Applies the pressure dependence of gas solubility to a solid.
  • Reads 'Henry's law constant' as a universal constant rather than one fixed for a gas at one temperature.

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