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NEET-UG and JEE Main Chemistry · Class 12

Elevation of boiling point and depression of freezing point — NEET & JEE Questions

Elevation of boiling point and depression of freezing point is a topic in Solutions, a Class 12 Chemistry chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 52 published NEET-UG and JEE Main questions on Elevation of boiling point and depression of freezing point, each with the marking scheme of the real paper.

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Elevation of boiling point and depression of freezing point MCQs with solutions

10 of the 52 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    For a dilute solution of a nonvolatile solute, elevation of boiling point is proportional to

    • A. molality
    • B. molarity only
    • C. solution density only
    • D. solvent volume only
  2. Question 2 · difficulty L2 · understanding

    A solution containing 2 g2 \mathrm{~g} of a non-volatile solute in 20 g20 \mathrm{~g} of water boils at 373.52 K373.52 \mathrm{~K}. The molecular mass of the solute is ___________ g mol−1\mathrm{g} ~\mathrm{mol}^{-1}. (Nearest integer) Given, water boils at 373 K, Kb373 \mathrm{~K}, \mathrm{~K}_{\mathrm{b}} for water =0.52 K kg mol−1=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}

  3. Question 3 · difficulty L2 · understanding

    1.80 g1.80 \mathrm{~g} of solute A was dissolved in 62.5 cm362.5 \mathrm{~cm}^{3} of ethanol and freezing point of the solution was found to be 155.1 K155.1 \mathrm{~K}. The molar mass of solute A is ________ g mol−1\mathrm{mol}^{-1}. [Given : Freezing point of ethanol is 156.0 K. Density of ethanol is 0.80 g cm −-3 . Freezing point depression constant of ethanol is 2.00 K kg mol −-1 ]

  4. Question 4 · difficulty L2 · understanding

    150 g150 \mathrm{~g} of acetic acid was contaminated with 10.2 g10.2 \mathrm{~g} ascorbic acid (C6H8O6)\left(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{6}\right) to lower down its freezing point by (x×10−1)∘C\left(x \times 10^{-1}\right)^{\circ} \mathrm{C}. The value of xx is ___________. (Nearest integer) [Given Kf=3.9 K kg mol−1\mathrm{K}_{f}=3.9 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}; molar mass of ascorbic acid =176 g mol−1=176 \mathrm{~g} \mathrm{~mol}^{-1}]

  5. Question 5 · difficulty L2 · understanding

    The elevation in boiling point for 1 molal solution of non-volatile solute A is 3 K3 \mathrm{~K}. The depression in freezing point for 2 molal solution of A\mathrm{A} in the same solvent is 6 KK. The ratio of KbK_{b} and KfK_{f} i.e., Kb/KfK_{b} / K_{f} is 1:X1: X. The value of XX is [nearest integer]

  6. Question 6 · difficulty L2 · understanding

    A solution containing 2.5 ×\times 10 −-3 kg of a solute dissolved in 75 ×\times 10 −-3 kg of water boils at 373.535 K. The molar mass of the solute is ____________ g mol −-1 . [nearest integer] (Given : K b (H 2 O) = 0.52 K kg mol −-1 and boiling point of water = 373.15 K)

  7. Question 7 · difficulty L2 · understanding

    40 g of glucose (Molar mass = 180) is mixed with 200 mL of water. The freezing point of solution is __________ K. (Nearest integer) [Given : K f = 1.86 K kg mol −-1 ; Density of water = 1.00 g cm −-3 ; Freezing point of water = 273.15 K]

  8. Question 8 · difficulty L2 · understanding

    83 g of ethylene glycol dissolved in 625 g of water. The freezing point of the solution is ____________ K. (Nearest integer) [Use : Molal Freezing point depression constant of water = 1.86 K kg mol −-1 ] Freezing Point of water = 273 K Atomic masses : C : 12.0 u, O : 16.0 u, H : 1.0 u]

  9. Question 9 · difficulty L2 · understanding

    When 3.00 g of a substance 'X' is dissolved in 100 g of CCl 4 , it raises the boiling point by 0.60 K. The molar mass of the substance 'X' is ______________ g mol −-1 . (Nearest integer). [Given K b for CCl 4 is 5.0 K kg mol −-1 ]

  10. Question 10 · difficulty L2 · understanding

    2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is: (Given : Ebullioscopic constant of water =0.52 K kg mol−1=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1} )

    • A. 377.3 K
    • B. 379.2 K
    • C. 375.3 K
    • D. 277.3 K

Common mistakes in Elevation of boiling point and depression of freezing point

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Adds $K_b$ and molality rather than multiplying.
  • Ignores the number of solute particles produced by dissociation.
  • Assumes equal formula-unit molality means equal particle concentration.

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