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NEET-UG and JEE Main Chemistry · Class 12

Osmosis and osmotic pressure — NEET & JEE Questions

Osmosis and osmotic pressure is a topic in Solutions, a Class 12 Chemistry chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 26 published NEET-UG and JEE Main questions on Osmosis and osmotic pressure, each with the marking scheme of the real paper.

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Osmosis and osmotic pressure MCQs with solutions

10 of the 26 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    Osmosis is the spontaneous movement of solvent through a semipermeable membrane from

    • A. lower solute concentration to higher solute concentration
    • B. higher solute concentration to lower solute concentration only
    • C. higher pressure to lower pressure in every case
    • D. solute side to pure solvent side
  2. Question 2 · difficulty L2 · understanding

    The osmotic pressure of a living cell is 12 atm at 300 K. The strength of sodium chloride solution that is isotonic with the living cell at this temperature is ________ g L -1 . (Nearest integer) Given : R = 0.08 L atm K -1 mol -1 Assume complete dissociation of NaCl (Given: Molar mass of Na and Cl are 23 and 35.5 g mol -1 respectively.)

  3. Question 3 · difficulty L2 · understanding

    An artificial cell is made by encapsulating 0.2 M0.2 \mathrm{~M} glucose solution within a semipermeable membrane. The osmotic pressure developed when the artificial cell is placed within a 0.05 M0.05 \mathrm{~M} solution of NaCl\mathrm{NaCl} at 300 K300 \mathrm{~K} is ________ ×10−1\times 10^{-1} bar. (nearest integer). [Given : R=0.083 L bar mol−1 K−1\mathrm{R}=0.083 \mathrm{~L} \mathrm{~bar} \mathrm{~mol}^{-1} \mathrm{~K}^{-1} ] Assume complete dissociation of NaCl\mathrm{NaCl}

  4. Question 4 · difficulty L2 · understanding

    The osmotic pressure of a dilute solution is 7×105 Pa7 \times 10^5 \mathrm{~Pa} at 273 K273 \mathrm{~K}. Osmotic pressure of the same solution at 283 K283 \mathrm{~K} is _________ ×104Nm−2\times 10^4 \mathrm{Nm}^{-2}.

  5. Question 5 · difficulty L2 · understanding

    An aqueous solution of volume 300 cm3300 \mathrm{~cm}^{3} contains 0.63 g0.63 \mathrm{~g} of protein. The osmotic pressure of the solution at 300 K300 \mathrm{~K} is 1.29 mbar. The molar mass of the protein is ___________ g mol−1\mathrm{g} ~\mathrm{mol}^{-1} Given : R = 0.083 L bar K−1^{-1} mol−1^{-1}

  6. Question 6 · difficulty L2 · understanding

    At 27∘C27^{\circ} \mathrm{C}, a solution containing 2.5 g2.5 \mathrm{~g} of solute in 250.0 mL250.0 \mathrm{~mL} of solution exerts an osmotic pressure of 400 Pa400 \mathrm{~Pa}. The molar mass of the solute is ___________ g mol−1\mathrm{g} \mathrm{~mol}^{-1} (Nearest integer) (Given : R=0.083 L bar K−1 mol−1\mathrm{R}=0.083 \mathrm{~L} \mathrm{~bar} \mathrm{~K}^{-1} \mathrm{~mol}^{-1})

  7. Question 7 · difficulty L2 · understanding

    The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL −-1 is _____________. (Molar mass of glucose = 180 g mol −-1 , R = 0.083 L bar K −-1 mol −-1 ) (Nearest integer)

  8. Question 8 · difficulty L2 · understanding

    1.46 g of a biopolymer dissolved in a 100 mL water at 300 K exerted an osmotic pressure of 2.42 ×\times 10 −-3 bar. The molar mass of the biopolymer is _____________ ×\times 10 4 g mol −-1 . (Round off to the Nearest Integer) [Use : R = 0.083 L bar mol −-1 K −-1 ]

  9. Question 9 · difficulty L2 · understanding

    Solution A is prepared by dissolving 1 g of a protein (molar mass = 50,000 g mol -1 ) in 0.5 L of water at 300 K. Its osmotic pressure is xx bar. Solution B is made by dissolving 2 g of the same protein in 1 L of water at 300 K. Osmotic pressure of solution B is yy bar. Entire solution of A is mixed with entire solution of B at the same temperature. The osmotic pressure of resultant solution is zz bar. xx, yy and zz respectively are: (R = 0.083 L bar mol -1 K -1 )

    • A. 9.96×10−4;  9.96×10−4;  9.96×10−49.96 \times 10^{-4};\;9.96 \times 10^{-4};\;9.96 \times 10^{-4}
    • B. 9.96×10−4;  9.96×10−4;  19.92×10−49.96 \times 10^{-4};\;9.96 \times 10^{-4};\;19.92 \times 10^{-4}
    • C. 4.98×10−4;  4.98×10−4;  9.96×10−44.98 \times 10^{-4};\;4.98 \times 10^{-4};\;9.96 \times 10^{-4}
    • D. 4.98×10−4;  4.98×10−4;  4.98×10−44.98 \times 10^{-4};\;4.98 \times 10^{-4};\;4.98 \times 10^{-4}
  10. Question 10 · difficulty L2 · understanding

    A solution is prepared by dissolving 0.3 g of a non-volatile non-electrolyte solute 'A' of molar mass 60 g mol−160 \mathrm{~g} \mathrm{~mol}^{-1} and 0.9 g of a non-volatile non-electrolyte solute ' B ' of molar mass 180 g mol−1180 \mathrm{~g} \mathrm{~mol}^{-1} in 100 mLH2O100 \mathrm{~mL} \mathrm{H}_2 \mathrm{O} at 27∘C27^{\circ} \mathrm{C}. Osmotic pressure of the solution will be [Given: R=0.082 L atm K−1 mol−1\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} ]

    • A. 2.46 atm
    • B. 0.82 atm
    • C. 1.47 atm
    • D. 1.23 atm

Common mistakes in Osmosis and osmotic pressure

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Uses an inverse relation with concentration or temperature.
  • Assumes osmotic pressure is independent of solute concentration.
  • Applies the stopping pressure to the wrong side of the membrane.
  • Assumes isotonic solutions must have identical composition.

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