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NEET-UG and JEE Main Physics · Class 12

emf, internal resistance and combinations of cells — NEET & JEE Questions

emf, internal resistance and combinations of cells is a topic in Current Electricity, a Class 12 Physics chapter of the NEET-UG and JEE Main syllabus. TestBudy holds 19 published NEET-UG and JEE Main questions on emf, internal resistance and combinations of cells, each with the marking scheme of the real paper.

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emf, internal resistance and combinations of cells MCQs with solutions

10 of the 19 published questions on this topic, exactly as they appear in a test. Answers and worked solutions come with your result rather than on this page.

  1. Question 1 · difficulty L1 · recall

    The emf of a cell is the work done by the cell per unit

    • A. charge
    • B. current
    • C. resistance
    • D. power
  2. Question 2 · difficulty L2 · understanding

    When an external resistance of 5Ω5 \Omega is connected across terminals of a cell, a current of 0.25 A flows through it. When the 5Ω5 \Omega resistor is replaced by a 2Ω2 \Omega resistor, a current of 0.5 A flows through it. The internal resistance of the cell is ____\_\_\_\_ Ω\Omega.

  3. Question 3 · difficulty L2 · understanding

    In an electrical circuit, a battery is connected to pass 20C of charge through it in a certain given time. The potential difference between two plates of the battery is maintained at 15V. The workdone by the battery is __________J.

  4. Question 4 · difficulty L2 · understanding

    The battery of a mobile phone is rated as 4.2 V,5800 mAh4.2 \mathrm{~V}, 5800 \mathrm{~mAh}. How much energy is stored ir it when fully charged?

    • A. 87.7 kJ
    • B. 43.8 kJ
    • C. 48.7 kJ
    • D. 24.4 kJ
  5. Question 5 · difficulty L2 · understanding

    Given below are two statements : Statement-I : The equivalent emf of two nonideal batteries connected in parallel is smaller than either of the two emfs. Statement-II : The equivalent internal resistance of two nonideal batteries connected in parallel is smaller than the internal resistance of either of the two batteries. In the light of the above statements, choose the correct answer from the options given below.

    • A. Statement-I is false but Statement-II is true
    • B. Statement-I is true but Statement-II is false
    • C. Both Statement-I and Statement-II are false
    • D. Both Statement-I and Statement-II are true
  6. Question 6 · difficulty L2 · understanding

    In the given circuit, the terminal potential difference of the cell is :

    • A. 3 V
    • B. 4 V
    • C. 2 V
    • D. 1.5 V
  7. Question 7 · difficulty L2 · understanding

    The combination of two identical cells, whether connected in series or parallel combination provides the same current through an external resistance of 2Ω\Omega. The value of internal resistance of each cell is

    • A. 2Ω\Omega
    • B. 4Ω\Omega
    • C. 6Ω\Omega
    • D. 8Ω\Omega
  8. Question 8 · difficulty L3 · understanding

    Two cells of emfs 1 V and 2 V and internal resistance 2Ω2 \Omega and 1Ω1 \Omega, respectively connected in parallel, gave a current of 1 A through an external resistance. If the polarity of one cell is reversed, then value of current through the external resistance will be α5 A\frac{\alpha}{5} \mathrm{~A}. The value of α\alpha is ____\_\_\_\_.

  9. Question 9 · difficulty L3 · understanding

    Two identical cells, when connected either in parallel or in series gives same current in an external resistance 5 Ω5 ~\Omega. The internal resistance of each cell will be ___________ Ω\Omega.

  10. Question 10 · difficulty L3 · understanding

    Two cells are connected between points A and B as shown. Cell 1 has emf of 12 V and internal resistance of 3Ω\Omega. Cell 2 has emf of 6V and internal resistance of 6Ω\Omega. An external resistor R of 4Ω\Omega is connected across A and B. The current flowing through R will be ____________ A.

Common mistakes in emf, internal resistance and combinations of cells

Recorded against questions in this topic that are not shown above, so none of these points at an answer you can see on this page.

  • Ignores internal resistance when finding circuit current.
  • Adds the internal drop instead of subtracting it for a discharging cell.
  • Uses the parallel-cell result for cells in series.
  • Assumes maximum emf alone determines the best cell arrangement.

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